"We have 33 company members. We're from different schools but we just meet on Saturdays from 4:30 to 6:30, it's an after school activity,"

VOA: standard.2009.12.04

So the correct answer for titanium plus two Ar3d2 is going to be argon 3 d 2, whereas if we did not rearrange our order here 4s2 we might have been tempted to write as 4 s 2 so keep that in mind when you're doing the positive ions of corresponding atoms.

所以正2价钛离子,的正确答案是，然而如果我们不重新安排顺序,我们可能会写出2,所以请记住,它当你们在解关于原子,的正离子的时候。

麻省理工公开课 - 化学原理课程节选

and all those fun things that you do when you're 4 years old.

以及所有那些你四岁的时候会做的有趣的事情。

在空闲时间 - SpeakingMax英语口语达人

So, what we're saying is that we have n equals to 4, and m sub I being equal to negative 2.

我们说的是ｎ等于４,ｍｌ等于－２

麻省理工公开课 - 化学原理课程节选

Well, that then says after another 12 steps, 12+12+t we're down to a problem with size t of b over 4.

更进一步，也就是。

麻省理工公开课 - 计算机科学及编程导论课程节选

it becomes especially important 4 kids who're outsiders kids who are alienated within the school community, because those kids often feel like there's no safe haven for them in the school.

对于在学校里是局外人身份的孩子来说很重要,他们被学校集体所遗弃，因为他们常常觉得,在学校里面他们找不到避难所。

麻省理工公开课 - 媒体、教育、市场课程节选

there're 4 million people living in Brooklyn by itself.

在布鲁克林住着四百万人口。

在布鲁克林的生活 - SpeakingMax英语口语达人

Chapters 2 and 4 are really reviews of things that you probably already know something about, so they're reviews of basic chemistry.

第二章和第四章是对,一些你可能已经知道的,基础化学,蛋白质及生物化学知识的复习

耶鲁公开课 - 生物医学工程探索课程节选

So the big lesson of this game is-- i forgot what number we're up too-- I guess this is Lesson 4 I think.

这个博弈的重要结论,我忘了第几个了,我记得应该是第四个

耶鲁公开课 - 博弈论课程节选

So what do you do when you're a kid and you want 3 to count a little faster than 1 and 2 and 3 and 4 what is the simplest thing you do?

因此当你还是个孩子的时候,你想数得比1，2，3，4快一些3,最简单的方法是什么？

哈佛公开课 - 计算机科学课程节选

When we say that 2 + 2 = 4 or 2 + 3 = 5, we're saying something about numbers that our mind is able to grasp.

当我们说2+2=4或2+3=5时,我们是在讨论心灵可以掌握的数字

耶鲁公开课 - 死亡课程节选

So we've got four chords operating here and they're changing regularly.

这一段作曲家一共调用4个不同的和弦，它们不断有规则地改变。

耶鲁公开课 - 聆听音乐课程节选

So we have 4 plus 5, but we're actually not done yet, because it's c n minus, so if we have minus, we actually have an extra electron in our molecule.

我们有四个加上五个，但是我们实际上还没做完，因为这是个负离子，所以如果我们有这个负号，那么我们的分子实际上还有一个额外的电子。

麻省理工公开课 - 化学原理课程节选

If we want to talk about two hydrogen atoms, then we just need to double that, so that's going to be negative 2 6 2 4 kilojoules per mole that we're talking about in terms of a single hydrogen atom.

而要讨论两个氢原子，我们只需要把它乘以二，因此应该是负的，2624，千焦每摩尔,这就是单个的氢原子的情况。

麻省理工公开课 - 化学原理课程节选

So in our first structure, we would find for the nitrogen we have a formal charge 5 minus 4 minus 2, because we're starting with 5 valence electrons, so that is a formal charge of minus 1.

那么在我们的第一个结构中，我们发现氮的形式电荷量是五减去四4,再减去二，因为我们开始有五个价电子，因此它的形式电荷量是负一。

麻省理工公开课 - 化学原理课程节选

s1 So for the fourth period, now we're into the 4 s 1 3d for potassium here. And what we notice when we get to the third element in 4s2 and the fourth period is 3d that we go 4 s 2 and then we're back to the 3 d's.

对于第四周期到现在我们来到钾的1,然后我们返回到,我们注意到当我们看到第三个元素,第四周期我们来到,然后我们返回到。

麻省理工公开课 - 化学原理课程节选

So that explains probably most of the confusion here and you just want to be careful when you're reading the problems that that's what you read correctly. I think 4 everyone would now get the clicker question correct.

这可能解释了大部分人的混淆之处,你们读题目的时候一定要仔细,我相信现在每个人都能回答正确了,第三激发态，n等于。

麻省理工公开课 - 化学原理课程节选

So that doesn't make a difference for us when we're talking about neutral atoms, 4s because we would fill up the 4 s first, because that's lower in energy until we fill it, and then we just keep going with the d orbitals.

所以那对我们来说没什么不同,所以当我们讨论中性原子时，因为我们会首先填充，因为在我们填充它之前它的能量都较低，然后我们继续填充d轨道。

麻省理工公开课 - 化学原理课程节选

So carbon has four valence electrons, so if we talk about c 2, again we're going to start filling in our molecular orbitals, and now we're going to have eight electrons to fill into our molecular orbitals.

碳有4个价电子，所以如果我们考虑C2的话，同样，我们开始填分子轨道，现在我们有8个电子,要填入分子轨道。

麻省理工公开课 - 化学原理课程节选

So that's here, and if I knew they were choosing Right for sure, that's the probability of 1 that they're choosing Right, and if I choose Middle I get 4, that's here.

对应的是这个点,如果说对手肯定选右,即他们选右的概率是1,此时我选中的收益是4,就是这个点

耶鲁公开课 - 博弈论课程节选

l So, if we're talking about a 4 p orbital, and our equation is n minus 1 minus l, the principle quantum number is 1 4, 1 is 1 -- what is l for a p orbital?

我们方程是n减去1减去，主量子数是，4，1是1，--p轨道的l是多少？,学生：

麻省理工公开课 - 化学原理课程节选

I don't care how you do it on exams or on problem sets, but you do need to be aware that the 3 d once filled is lower in energy than the 4 s, and the reason you need to be aware of that is if you're asked for the electron configuration now of the titanium ion.

我不关心你们在考试或者,问题集中如何做它，但是你们的确需要知道3d一旦被填充,它的能量是小于4s的，你们需要知道这个的原因,是如果你现在被要求,写出钛离子的电子构型。

麻省理工公开课 - 化学原理课程节选

So we're throwing away all of the strategies less than 5/4 for Player I and bigger than 6/4 for Player I, which is 1? for Player I and similarly for Player II.

这样我们又剔除了,参与人小于5/4大于6/4的策略,参与人I只有1?的区间,同理可证参与人II

耶鲁公开课 - 博弈论课程节选

So if you look at the energy diagram, what we see is that the 4 s orbitals are they're just ever so slightly lower in energy than the 3 d orbitals.

如果你看能量图，我们看到的是4s轨道,他们仅仅比3d轨道,能量低一点点。

麻省理工公开课 - 化学原理课程节选

So, in other words, if we apply some of the storyline 4 5 6 from the previous tale, if s1 happens to be 4, 5, s2 4 5 6 you're just asking the question is 4, 5, 6 equals equals to 1, 2, 3?

换句话说，如果我们运用之前的一些情节,如果s1正好为，正好为1，2，3，6，and，s2，happens，to，be，1，，2，，3，你就会问：,等于1，2，3吗？

哈佛公开课 - 计算机科学课程节选