I first had a list of size 8, then 4, then 2, but then I had another problem of size 2.
首先是一个有8个元素的序列,接着变成了4个元素,接着2个元素,然后我就碰到了有2个元素的另一个问题。
d1 2 3 And we can do that just going along, 3 d 1, 2 3, and the problem comes when we get to chromium here, which is instead of what we would expect, 4s23d4 we might expect to see 4 s 2, 3 d 4.
我们能做的就是继续,问题出现了,当我们来到铬元素时,它不是我们预期的那样,我们可能预期。
The assignment for the next class is to do Problem 2 of Chapter 1, which I've repeated right here, and that's to think beyond what I've talked about in terms of what is Biomedical Engineering.
下次课的预习任务是做第一章课后习题二,我在这里重复一下,除了我已经说过的东西之外,去想一下什么是生物医学工程
Where you go from problem of size n to a problem of size n minus 1.
或者缩减了2,这都一样的,也就是把问题的规模从n变成了n-1。
If you see a problem that asks you, for example, the third ionization energy versus taking a second electron out of the 2 s in a photoelectron spectroscopy experiment, those are two very different things.
如果你遇到一个题目问你的是,比如说,是第三电离能,还是在光电子能谱实验中从,2,s,轨道中,拿走第二个电子,这可是两个完全不同的问题。
Same sort of subtraction problem, what do we have for the ionization energy of the 2 s electron?
进行类似的减法运算,得到的,2,s,电子的电离能应该是多大呢?
应用推荐