It's only got one of four possible choices at each position.

每个位点上都只有四种可能性

耶鲁公开课 - 生物医学工程探索课程节选

So you have a continuum of possible choices.

也就是说你的策略是连续的

耶鲁公开课 - 博弈论课程节选

If I have three, I have 16 x 4 or 64 possible choices, way more than enough.

那如果是三个碱基一组,那就有16x4种,六十四种组合,那就足够了

耶鲁公开课 - 生物医学工程探索课程节选

If I'm careful I should get this right 1, 2, 3, and 4 are the possible choices for Player I.

我好好画一下,这样会准确点,参与人I的可选策略从1一直到4

耶鲁公开课 - 博弈论课程节选