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The S & P Five Hundred index gained over twenty percent its largest increase in six years.
VOA: special.2010.01.01
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V So this nR over V. And then, using the relation again, T we can just write this as p over T.
恒定温度下的dp/dT等于nR除以，再次利用状态方程，可以把它写成p除以。
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du/dV So now our du/dV, dp/dT at constant T is just T times dp/dT which is just p over T minus p, it's zero.
现在我们的恒定温度下的，等于T乘以dp/dT，在这里,等于p除以T，最后再减去p，结果是0。
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So for example I defined p, remember back over here, as a Cartesian point, but I can actually ask for its polar form.
我可以要求返回它的极坐标形式，这里对我是可访问的，好，这很棒，请再记另外一个为什么。
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Remember, we didn't hybridize the 2 p y orbital, so that's what we have left over to form these pi bonds.
记住，我们并没有杂化2py轨道，这是我们剩下的那个行成了π键。
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pV=RT dT here because the pressure is constant, dV=RdT/p so dV is equal to R over p dT.
因为对1摩尔气体有，于是。
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OK, now, if I actually do this, and I'm going to show you the example, I just, what did I type over there, I got p was a c point.
传入了其他的参数，好，现在，如果我，实际上要做这个的话，我要给大家看个例子。
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pV=RT p plus a over v bar squared times v bar minus b equals r t. All right if you take a equal to zero, these are the two parameters, a and b. If you take those two equal to zero you have p v is equal to r t.
我们就回到,也就是理想气体,状态方程,下面我们来看看,这个方程。
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OK, and if I wanted to look at it, we can come back over here, and we can see what does c p 1 look like, interesting.
现在对于这里的每个实例，我都赋了x和y值，好，那么如果我想要研究下它,我们可以回到这里来。
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p So dV/dT at constant pressure is just nR over p.
所以恒定压强下dV/dT等于nR除以。
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We want a relationship in p-V space, not in T-V space. So we're going to have to do something about that. But first, it turns out that now we have this R over Cv.
我们想要p-V空间中的结果，而不是T-V空间中的,因此需要做一些变换，先来看现在的关系，它跟R/Cv有关。
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Minus p, right? But in fact, if you go back to the van der Waal's equation of state b here's RT over v minus b.
再减去p，对吗，但是实际上，如果你代回范德瓦尔斯气体的状态方程,这里是RT除以摩尔体积减去。
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So instead of p, here I'm going to put nRT over V.
于是把p写成。
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So I can instead of the dV here, I can insert this R over p dT.
两个p消掉了，结果。
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