• sigma2sp It's going to be a sigma bond. So, we have sigma 2 s p, carbon 2 s p. So they're two s p bonds combining.

    是sigma键,我们有,碳2sp。,所以它们是两个sp键结合。

    麻省理工公开课 - 化学原理课程节选

  • Remember, we didn't hybridize the 2 p y orbital, so that's what we have left over to form these pi bonds.

    记住,我们并没有杂化2py轨道,这是我们剩下的那个行成了π键。

    麻省理工公开课 - 化学原理课程节选

  • So, what we end up having is three of these pi -- 2 p y 2 p y bonds, we can have one between these two carbons here.

    我们剩下的有三个π键-,2py2py键,在这两个碳原子之间会有一个。

    麻省理工公开课 - 化学原理课程节选

  • So, if we think about what bonds are in this molecule, sp2 we actually have six of these sigma carbon s p 2, carbon s p 2 bonds.

    如果我们考虑这个分子里都有什么键,我们有六个sigma碳,碳sp2键。

    麻省理工公开课 - 化学原理课程节选

  • We also have carbon s p 2 hydrogen 1 s bonds.

    我们还有碳sp2氢1s键。

    麻省理工公开课 - 化学原理课程节选

  • There's not two bonds, that's one pi bond, and the reason is because it's 2 p orbitals coming together, and remember p orbitals have electron density above and below the axis, so when they come together, it kind of looks like one bonds, but essentially what we have here is one pi bond.

    这不是两个键,这是一个π键,因为这是两个2p轨道组合而成的,记住p轨道在键轴之上,和键轴之下都有电子密度,当它们靠近时,这看着很像两个键,但本质上它是一个π键。

    麻省理工公开课 - 化学原理课程节选

  • So if we still have an angle of a 109 . 5 degrees, and again, we still have four unpaired electrons available for bonding, we can make one of those bonds with another s p 3 hybridized carbon, so we're going to make up one pair here.

    如果键角仍然是109。,同样,我们还有4个未配对的电子可以用来成键,我们可以用其中的一个,和另外一个sp3杂化碳原子成键,这样我们可以组成一对。

    麻省理工公开课 - 化学原理课程节选

$firstVoiceSent
- 来自原声例句
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定
小调查
请问您想要如何调整此模块?

感谢您的反馈,我们会尽快进行适当修改!
进来说说原因吧 确定