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All right, c p 1 dot y, x I've said assign that to the value 2, 2,0. So now c p 1 has inside of it an x and y value.
一个特定的版本，我现在命名了一个内置变量，并给它赋值了,我刚刚做的也就是给它。
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And if we talk about m equals 0, we're looking at the p z orbital.
如果ｍ等于０，那我们讨论的就是ｐｚ轨道。
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which is f , divided by the value of the x-axis here.
斜率，而f是p趋于0时pV的极限。
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Did the same thing with c p 2, 2 2 0 Again, remind you, c p 2 is a different instance of this data type.
建立了一个x变量，我也把它赋值为，因此cp1内置有了x和y值,然后对cp2做同样的操作。
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I have the case where p = .2, so the probability of an accident is 20%.
假设这里的p等于0.2,也就是一次事故发生的概率为20%
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Basically if you have a number that's P in this case, than the number is lower then that shows increasing level of statistical significance.
基本上如果P,这幅图里的数比0.05更小,数字越小,表示统计学显著性越大
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I'm going to call it r. It's going to be the gas constant, and now I have r times t is equal to the limit, p goes to zero of p r.
如果去掉p趋于0的条件,在有限压强下都,保持RT=pV的关系。
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So you should know that 0 any time m is equal to zero that it's the p z.
所以当我们讨论p轨道时,只要m等于,它就是pz轨道。
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The property is the limit as p goes to zero of pressure times molar volume.
与摩尔体积的乘积,在气体压强p趋于0时的极限。
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p And for example, 0 we could also in this case, have m is equal to 0.
轨道，The，p，orbital。,又例如，这种情况中，令m等于。
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And so now we have this quantity, p times v bar, and the limit of p goes to zero is equal to a constant times the temperature.
不仅仅对氢气或氮气适用，在p趋于0的极限下,它适用于任何气体。
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I'm pressing on the gas. So I expect that to be a positive number. The pressure is constant 0 p. The V goes from V1 to zero.
我们对气体加压,所以这应该是一个正数,压强是常数，p，V从V1变成。
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And so they defined them, p after many experiments, the limit of this 0 delta T delta p and the limit of delta p goes to zero as the Joule-Thomson coefficient.
他们定义了这些量，以及它们的范围，ΔT比Δ,Δp的极限趋近于,叫做焦耳-汤姆逊系数。
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du/dV So now our du/dV, dp/dT at constant T is just T times dp/dT which is just p over T minus p, it's zero.
现在我们的恒定温度下的，等于T乘以dp/dT，在这里,等于p除以T，最后再减去p，结果是0。
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If m is equal to 0, in this case we would call it the p z orbital, z so we would have the subscript z here.
如果m等于0，这种情况下,我们叫它pz轨道，我们在这里有下标。
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In which I said c p 1 dot x equals 1.0.
请注意我上面是怎么做的,创建了cp1和cp2后。
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