-
That means that p1 and -- where I am, the point number 1 and point number 2 were completely arbitrary.
因为1和，两个点是2,陆军上面。
-
Sorry, said that wrong, p1 radius 1 and angle 2, 2 radians is a little bit more than pi half.
而是半径和角度的表示，在这个例子中点，并不对应这个点,它实际上对应的是。
-
We start at p1, V1. and p external is equal to zero.
从状态开始，外部压强为零。
-
So they're going to P1, will the price of Firm 1, and P2 will be the price of Firm 2.
所以P1代表,公司1的价格,而P2代表公司2的价格
-
There is p1 sitting here, and all of the gas is sitting on that side of the plug.
所有的气体都在节流阀的这一边,在我们完成了实验之后。
-
So this guy here gets rid of this, and I have my answer as V1 over V2 to =p2/p1 the gamma power is equal to p2 over p1.
这两项抵消掉了，于是等式,变成了^γ
-
Each weighing, say, one 100th of the weight 1/100 needed to establish p external is equal to p1.
每颗重，比方说，使外压强,达到p1的重量的。
-
p1 But if I say, are p 1 and p 2 the same point, it says yes.
和p2是不是同一个点，It，says，no。,返回的结果是肯定的，在这里我有个要强调的点，这个例子里发生的是。
-
W2 If I go backwards, to work p1 becomes the negative from what I had p2 calculated before, so this becomes minus what I calculated before for w2.
应该是,总功等于,减去,等于。
-
p We want p equal to p external for the entire expansion, p2 and p external is decreased steadily from p1 to p2.
在膨胀过程中保持p等于外部，外部p很快从p1衰减到。
-
So now, instead of having p external p2 equals to p2 here, I put p1 and I let this whole thing go reversibly.
也就是说,现在开始的外界压强不是，而是p1，整个过程都是可逆的。
-
p2 It's taking the name p 1 and it's changing its value to point to exactly what p 2 points to.
我要把p1赋值为1,这个操作有什么用呢？,这个操作把p1这个名字的,指针的值改变让它。
-
w=p1v1 So we write down p1, V1.
我们写下。
-
You're pushing through here. p1 is greater than p2.
你们从这儿慢慢推动它。
-
Then I'm going to release these little pegs here and my piston is going to shoot up now p1 because p2 is less than p1.
现在移开插销,活塞就会往上冲,因为p2小于。
-
Wrev So minus w reversible, 1 p2 is less than p1, so p2 over p1 is less than one, log of something less than 1 is negative times negative.
那么，而p2小于p1，p2/p1小于，取对数后是负数,负负得正。
-
p2/p1 Then I'm going to get, be left with a p2 over p1.
于是右边剩下。
-
p1 V1 OK, so in my diagram now, I have p1, V1 for my gas.
于是可以画出现在的p-V图。
-
Then you take p1 to p2 with V constant.
图上画出来就是这样。
-
I take V1 to V2 first, keeping the pressure constant at p1, then I take p1 to p2 keeping the volume constant V2 at V2. Let's call this path 1.
容易计算的路径，第一条路径，是首先保持压强不变,体积从V1压缩到。
-
If p2, the pressure in p2, is less than the pressure in p1, is the gas going to want to go from p2 to p1 and the whole thing reverse back?
比p1中的压强小,在整个逆向过程中气体,会从p2到p1中去吗？
-
v1=/p1 So V2 = /p2, and V1 = /p1.
因此v2=/p2，同样地。
-
p2 p1 is greater than p2. Then I want to reverse direction of time. I want the arrow of time to go so that the gas goes from p2 to p1.
一直推，一直推，p1大于,接下来我想让时间倒流,让气体从p2到p1。p2比p1小。
-
I going to come back in a second to how it actually does that, but it basically says, get me x value for p 1, get me the x value for p 2, compare them, just as you would normally.
是一个类的实例,我要去取的这个实例，所关联的x值，我稍后会讲讲实际上，这里是怎么实现的，但是基本上它的意思就是，给我p1的x值。
-
V2 p1 times V2 minus V1. What that turns out to be, 0 this area right here. It's V1 minus V2 times p1.
第二步做的功是-pdV，积分从V2到，这部分积分出来是多少？应该是。
-
It's nR log of p2 over p1 for the process where there's a pressure change.
结果是dS等于nR乘以p2除以p1的对数,这是对压强变化的结果。
-
So on the p-V diagram, then, V1 V2 p1 p2 there's a V1 here a V2 here, a p1 here a p2 here.
在p-V图上，这是。
-
p1 So p2 is less than p1, the external pressures is less than the internal pressure.
抱歉，应该是p2小于,外界压强小于内部压强。
-
So any point I pick on that path will be equal to p1, V1 to the gamma.
也就是说路径上面任取一个点,计算p，V^γ
-
p1/p2 So, the nRT's cancel, and we have p1 over p2.
因此nRT相消，结果就是。
应用推荐