-
According to U.N.officials, the attacks on civilians have been increasing and pouring over into surrounding areas.
VOA: standard.2009.08.27
-
One over two squared minus one over n squared 3 4 5 where n takes values three, four, five, six.
除以，2，的平方再减去1除以n的平方,将n赋值为。
-
And I know a lot of people over at NYU for N Tisch, and it's very highly competitive.
我认识很多人为了N Tisch去纽约大学，竞争相当激烈。
-
But,the U.N.Humanitarian Coordinator in Pakistan,Martin Mogwanja, says the crisis is far from over.
VOA: standard.2009.09.25
-
So instead of being equal to negative z squared, now we're equal to negative z effective squared times r h all over n squared.
这里不再等于-z的平方，现在我们等于-有效的z的平方,乘以RH除以n的平方。
-
Mitchell said he is not discouraged about his mission's recent setbacks, including acrimonious exchanges over a recent U.N.report alleging possible war crimes in last year's Gaza conflict, citing the example of his successful Northern Ireland peace efforts in the 1990s.
VOA: standard.2009.11.25
-
e The charge on the anion times minus e, so there is the minus e squared, 0R0 and divided by 4 pi epsilon zero r naught, because now I am evaluating this function at r naught, one minus one over n where n is the Born exponent.
阴离子的电荷乘以，因此会有-e的频繁，除以4πε,因为现在我用r圈评估这个函数，1-1/n，n是波恩指数。
-
Right. N is over here for counting from zero.
对的，从0开始计数，N到了这边。
-
If I want to move this stack here, I'm going to take a stack of size n minus 1 move it to the spare spot, now I can move the base disk over, and then I'm going to move that stack of size n minus 1 to there. That's literally what I did, OK?
如果我想移动这些圆盘，我先把从n-1个圆盘1,移动到多余的柱子上去，这样我就能把最底下的圆盘放到这儿了，然后再把从n-1个圆盘放到这儿来,这就是确切的我怎么做的对不对？
-
And that's going to be equal to negative z effective squared times r h over n squared.
有效的z的平方,乘以RH除以n的平方。
-
So we know that we can relate to z effective to the actual energy level of each of those orbitals, and we can do that using this equation here where it's negative z effective squared r h over n squared, we're going to see that again and again.
我们知道我们可以将有效电荷量与,每个轨道的实际能级联系起来，我们可以使用方程去解它,乘以RH除以n的平方,它等于负的有效电荷量的平方,我们将会一次又一次的看到它。
-
We're going to get to more complicated atoms eventually where we're going to have more than one electron in it, but when we're talking about a single electron atom, we know that the binding energy is equal to the negative of the Rydberg constant over n squared, so it's only depends on n.
我们以后会讲到，更加复杂的情况,那时候,不只有一个原子，但当我们讲，单个原子的时候，我们知道结合能，等于,负的Rydberg常数,除以n平方，所以它仅仅由n决定的。
-
n*pi/L It turns out it is n pi over l.
结果是。
-
So instead you'd have to maybe if you start with wavelength, go over there, and then figure out velocity and do something more like kinetic energy equals 1/2 n b squared to get there.
这时你要先从波长开始，到这，然后算出速度,然后像动能等于1/2nb平方得到这。
-
Times the square of the elementary Z charge times n squared over Z.
乘以元电荷的平方,乘以n的平方除以。
-
So the square root of n squared r e over r h.
这里的n值是什么呢？
-
So, if we just rearrange this equation, what we find is that z effective is equal to n squared times the ionization energy, IE all over the Rydberg constant and the square root of this.
我们可以发现有效的z等于n的平凡，乘以电离能除以里德堡常数,这些所有再开方，所以等于n乘以,除以RH整体的平方根。
-
So, we can get from these energy differences to frequency h by frequency is equal to r sub h over Planck's constant 1 times 1 over n final squared minus 1 over n initial squared.
所以我们通过不同能量,得到不同频率，频率等于R下标,除以普朗克常数乘以1除以n末的平方减去。
-
Bohr said that the angular momentum, mvr where n is this integer counter h over 2 pi.
波尔提及到角动量，是被量化了的，mvr，is，quantized,这里的n等于一个整数乘以h除以2π
-
Log n Log n, because at each stage I'm cutting the problem in half. So I start off with n then it's n n/2 n/4 n/8 over two n over four n over eight.
因为总共有多少层？,因为在每一层，我都是把问题分解成两半,因此以n开始，然后是。
-
So, it's negative Rydberg constant over n squared.
它等于负的Rydberg常数，除以n平方。
-
So kind of that strange cursive r, and our n final is 2, R so 1 over 2 squared minus n initial, so 1 over 3 squared.
因为我们可以在这里用到它，这个有点奇怪的花体。
-
Up here I have n over two operations of size two. Up here I've got n over four operations of size four.
最下面有n个规模为1的操作,接着上面有n/2个规模为2的操作,再上面有n/4个规模为4的操作。
-
s We are back over to E as a function of n, l, m and s, only we got there through this other torturous route.
我们回到将E作为函数n，l和，只要我们解决了这个烦人的路径。
-
We also know how to figure out the energy of this orbital, and we know how to figure out the energy using this formula here, which was the binding energy, -Rh which is negative r h, we can plug it in because n equals 1, so over 1 squared, and the actual energy is here.
我们知道如何算出,这个轨道的能级，而且我们知道如何,用这个公式,算出能量，也即是结合能，等于，我们把n等于1代进来，所以除以1的平方，这就是能量。
应用推荐