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VOA: special.2009.09.30

Well, the energy of the photon, hv we know from Planck, is h nu, which is hc over lambda.

好吧，光子，我们从普朗克那得知，它是，即hc/lambda，波长。

麻省理工公开课 - 固态化学导论课程节选

Bohr said that the angular momentum, mvr where n is this integer counter h over 2 pi.

波尔提及到角动量，是被量化了的，mvr，is，quantized,这里的n等于一个整数乘以h除以2π

麻省理工公开课 - 固态化学导论课程节选

So instead of being equal to negative z squared, now we're equal to negative z effective squared times r h all over n squared.

这里不再等于-z的平方，现在我们等于-有效的z的平方,乘以RH除以n的平方。

麻省理工公开课 - 化学原理课程节选

So we can figure out the energy of each photon emitted by our UV lamp by saying e is equal to h c over wavelength.

所以我们可以计算出,每个从紫外光源射出的光子,也就是e等于h乘以c除以波长。

麻省理工公开课 - 化学原理课程节选

And that's going to be equal to negative z effective squared times r h over n squared.

有效的z的平方,乘以RH除以n的平方。

麻省理工公开课 - 化学原理课程节选

So we know that we can relate to z effective to the actual energy level of each of those orbitals, and we can do that using this equation here where it's negative z effective squared r h over n squared, we're going to see that again and again.

我们知道我们可以将有效电荷量与,每个轨道的实际能级联系起来，我们可以使用方程去解它,乘以RH除以n的平方,它等于负的有效电荷量的平方,我们将会一次又一次的看到它。

麻省理工公开课 - 化学原理课程节选

So the square root of n squared r e over r h.

这里的n值是什么呢？

麻省理工公开课 - 化学原理课程节选

So, we can get from these energy differences to frequency h by frequency is equal to r sub h over Planck's constant 1 times 1 over n final squared minus 1 over n initial squared.

所以我们通过不同能量,得到不同频率，频率等于R下标,除以普朗克常数乘以1除以n末的平方减去。

麻省理工公开课 - 化学原理课程节选

We also know how to figure out the energy of this orbital, and we know how to figure out the energy using this formula here, which was the binding energy, -Rh which is negative r h, we can plug it in because n equals 1, so over 1 squared, and the actual energy is here.

我们知道如何算出,这个轨道的能级，而且我们知道如何,用这个公式,算出能量，也即是结合能，等于，我们把n等于1代进来，所以除以1的平方，这就是能量。

麻省理工公开课 - 化学原理课程节选