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All right, so the bonding order, you're correct, should be 2, if we subtract the number of bonding minus anti-bonding electrons and take that in 1/2.

好，你们是对的，键序为，如果我们用成键数,减去反键数除以2。

麻省理工公开课 - 化学原理课程节选

The way that we can figure this out is using something called bond order, and bond order is equal to 1/2 times the number of bonding electrons, minus the number of anti-bonding electrons.

我们可以用叫做,键序的概念来弄明白它，键序等于1/2乘以成键电子,数目减去反键电子数目。

麻省理工公开课 - 化学原理课程节选

Now, the critical thing to understand about a corporation is that in order to value a share in a corporation you absolutely have to know the number of shares outstanding.

理解这类公司的关键在于,要衡量一家公司股票的价值,你必须清楚总共发行的股票数量

耶鲁公开课 - 金融市场课程节选

We'll think about it in section, how you don't need to vaccinate everybody, but you just need to vaccinate a critical number in order to stop the disease from progressing through a community.

我们在讨论会上讲这个,为什么不需要给每个人都接种,但你只需要让接种人数达到一个临界值,就能阻止这个疾病在社会中传播

耶鲁公开课 - 生物医学工程探索课程节选

So then in order to figure out the complete number of valence electrons in our molecule, we just add 5 plus 4 plus 1.

那么接下来为了得到,这个分子中价电子的总个数，我们只需要将五加上四，再加上一。

麻省理工公开课 - 化学原理课程节选

So for the bond order we want to take 1/2 of the total number of bonding electrons, so that's going to be 4 minus anti-bonding is 4, so we end up getting a bond order that's equal to 0.

键序等于1/2乘以,总的成键电子数，也就是4，减去反键电子数，也就是4。,所以最后得到键序为0。

麻省理工公开课 - 化学原理课程节选

If you're trying to prevent a disease that only occurs at a rate of 20 per 100,000 people you have to give the vaccine to millions in order to see if the number goes down.

如果你尝试去防治一个,发病概率为十万分之二十人的疾病,那么就必须将疫苗分发给数百万人,以观察疫苗能否降低发病率

耶鲁公开课 - 生物医学工程探索课程节选