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VOA: standard.2010.02.20
I also want to assume for our present purposes that there's only pressure volume work going on, which is to say I want to put pdV p dV in here minus p dV for dw.
同时假定,对于我们目前的目的而言,只有压强做功这就是说,我要把这里的dw替换为负。
What is this orbital? Yup. And there's only 2pz one correct answer here, which is to 2 p z.
它的轨道是什么?,嗯,这里,只有一个答案,那就是。
Well, the initially tempting thing to say is not only aren't you broken, but you're actually engaged in P-functioning.
首先要说的会是,不仅你没有被破坏,还有确实,拥有人格功能性。
And the useful outcome of all that is that p we get to see how entropy changes with one of those variables in terms of only V, T, and p, which come out of some equation of state.
这样做的重要结果是,我们得到了熵随着V,T或者,其中一个变量变化的情况,这些可以从状态方程得到。
So I'll be producing this stuff, this water at cost c and only getting p, which is not only less than c in return.
这就导致成本是c的瓶装水只能卖到p,这个价格都不能捞回本钱呢
So it turns out that during that period in which they were dead, they were only temporarily not P-functioning.
那么在他们死去的那段时间,他们只是暂时没有人格功能性。
They were only temporarily not P-functioning, just like we are temporarily not P-functioning when we're asleep.
只是暂时失去了人格功能性,就像我们睡觉时,暂时没有人格功能性一样。
So if we compare l increasing here, so a 3 s to a 3 p to a 3 d, what we find is that it's only in the s orbital that we have a significant probability of actually getting very close to the nucleus.
我们比较当l变大的时候,从3s到3p到3d,我们可以发现只有s轨道,有很大的概率,非常接近原子核。
Adiabatic q equal to zero. It's also delta H 0 which is zero. The two didn't necessarily follow because remember, delta H is dq so p is only true for a reversible constant pressure process.
在这个过程中ΔH等于,绝热的所以q等于0,而ΔH也等于,这两个也不一定有因果关系,因为,记住,ΔH等于dq只有在恒压。
So if we don't have to hybridize one of the p orbitals, we can actually end up with a lower energy situation, because now these s p 2 orbitals are 1/3 s character, and only 2/3 p character, instead of 3/4.
我们的杂化轨道就有更多的p轨道成分,所以它们的能量更高,如果我们不杂化这个p轨道,我们可以得到一个能量更低的情况。
All right, so that's s p 3 hybridization, but those aren't the only type of hybrid orbitals that we can form. Let's take a look at what happens if instead of combining all four orbitals, we just combine three of those orbitals, and what we'll end up with is s p 2 hybridization.
好了,这是sp3杂化,但这并不是我们可以,形成的唯一类型的杂化轨道,让我们来看看,不是四个轨道结合,我们仅仅结合3个轨道。
Only V, p and T appear.
只有体积V,压强p和温度T出现。
All right, so one thing that I want to point out, which I said many, many times on Friday, and this is perhaps the last time I'll say it, but one last time is we can think about why we only see a line for the 2 p orbital, versus we don't see separate lines for a 2 p x, a 2 p y, and a 2 p z.
好的,我还要指出一个问题,这个问题我在上周五已经说了很多很多次了,这可能是我最后一次提到它,但是这最后一次让我们来考虑一下,为什么我们只看到了一条,对应于,2,p,轨道的线,而不是分别对应于,2,p,x,2,p,y,2,p,z,的线?
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