The heads of state at the AU's last summit had asked the U.N.Security Council to use its power to defer the Bashir indictment for one year.
VOA: standard.2009.07.06
That energy will be absorbed by the hydrogen atom, n=1 the electron will rise from n equals one n=2 to n equals two.
这能量将会被氢原子吸收,这个电子会从,上升到。
There are some relative, the notion that the energy gap between n equals one and n equals two is greater than that for n equals two to n equals three. That is correctly represented.
还有很多与之相关的内容,比如说这个观点,第一能量级和第二能量级,之间的能量差要大于第二和第三能量级间的,能量差,而这已经被正确地表示出来了。
"This is one of the clearest calls repeatedly rendered to the government of Sri Lanka - that the U.N.be allowed to access the area so we can assess independently the situation of civilians,"
VOA: standard.2009.05.11
So in other words, every time I merge the point that I kept emphasizing verbally there and that I'm only touching each number once, means that we have to account for the amount of time it takes to merge N which is going to be just N. Now, this is again one of these cyclical answers.
换言之,之前在做合并时,我不停地强调,对每个数字我只碰了一次,这就是说,我们要记录合并所花的时间量,也就是这里的,这又是一种循环性的答案。
So if you're trying to make a more complicated organic molecule carbon-carbon bonds are one of the most difficult things to make in organic chemistry, and it turns out that c n minus is a very reactive molecule, so it's a good way, even though we'll go over some drawbacks in a second, it is a good way to make carbon-carbon bonds.
如果你要合成一个更复杂的有机分子,碳碳键是有机化学中,最难制造的键之一,而实际上氰离子是一种具有很高活性的分子,用它是一个好办法,尽管我们一会儿将看到它的一些缺点,但它的确是一个制造碳碳键的好方法。
It depends on n and k but obviously as n gets big, that one is going to be better.
但是很明显,当n取很大的值的时候,前者要比后者好。
If you start with only one, you have two pieces of DNA, then you'll get 2 to the Nth fragments after N cycles because each cycle you're doubling the number.
如果你从仅仅一个DNA开始,你有两条DNA链,经过N次循环后,就得到二的N次方个DNA片段,因为每次循环都使其数量翻倍
And if that is the energy to go from n equals one n=2 this is the amount of energy that has to be left as kinetic energy of the electron.
如果这个能量是从n=1到,然后,to,n,equals,two,then,这些能量,会作为电子的动能,被消耗掉。
psi So we're going to for psi, and before that, we're going to figure out that instead of n just that one quantum number n, we're going to have a few other quantum numbers that fall out of solving the Schrodinger equation for what psi is.
我们要讲到,但在这之前,我们已经知道了,主量子数,现在我们需要知道,其他一些,解psi的薛定谔方程,所需要的量子数。
So we are going to put atomic hydrogen Z equals one, 1 ground state n equals one.
氢原子Z等于,基态n也等于。
So this line or these lines of code up here are arguably constant time steps to say if N is less than 2 in return, that it will always take maybe one step, maybe two steps, some number of fixed CPU cycles.
如果N小于2并返回,那么这些行所对应的代码,通常只需要执行一步,或者两步,具体数字与CPU周期有关。
So there are two electron configurations in the n equals one shell, if we follow according to the selection rules that we spelled out last day.
如果根据上次课,我们阐明的原子光谱选择定则,我们就会知道在n等于1的那一层,有两种电子图像构型。
If they type in bogus characters, it's going to yell at them and make them retry, and eventually I'm going to get handed back an int, which I'm storing in n. Well, if I actually want to judge this number based on its magnitude, well, I can say now, "If n is greater than or equal to one."
如果他们键入了不合法的字符,它将对他们叫喊,然后叫他们重试,最终我将,得到一个int数,它是存储在n中的,好的,如果我的确想要根据它的量级来判定这个数字,好的,现在我可以指明,“是否n大于等于1“
All right, I want to do one more at homonuclear example here, and this is n 2.
好的,我想要再讲一个同核的例子,这就是N2。
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