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Club America is in second place after a 2-1 win over AC Milan on Wednesday in Atlanta and a penalty shootout win over Inter Milan last Monday in California.
VOA: standard.2009.07.25
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So, we need to actually add on this fourth quantum number, 1/2 and it's either going to be plus 1/2 or negative 1/2.
所以我们需要加上这第四个量子数，它等于1/2或者负的。
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So, if you compartmentalize things in your brain in certain ways, put that off into the end of the exam 1 part of your brain, and now we're going to move on to exam 2.
如果你喜欢以自己的方式将信息在大脑中分开储存，这就是你大脑里对第一次考试的分区所存储的全部内容，而接下来我们将继续将第二次考试的内容。
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The second problem is, 1 suppose actually I had p 1 and p 2 were in polar form, and I ran add points on them.
第二个点也就是，半径为3角度为1,也就是差不多在这，那么什么点，对不起。
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And in this case, we go from 8 to 4 to 2 to 1 three times and then on each iteration of this algorithm, each pass across the board I'm touching N numbers, so that means I'm doing N things, log N times.
在这个例子中，我们从8得到4，到2，再到1，是3次,在这个算法的每次迭代中，每一趟我都会操作N个数，也就是所我每次要做N步操作，一共要做，log，N，次。
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That may be t=0, t=1, t=2 and so on.
也就是 t=0,t=1,t=2 等等
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And the bond order you get out will either be, for example, zero, which would mean that you have no bond, 5 or you could have 1, a single bond, 1 . 5, a 1 and 1/2 bond, 2, a double bond, and so on.
你得到的键序要么是比如说是零，这意味着没有键，或者你会得到1，单键1。,1又二分之一键，2，一个双键，等等等等。
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If we look at our last structure here where we have nitrogen the middle, we can also figure out all those formal charges, and in this case we have plus 1 on the nitrogen, we have minus 2 on the carbon, and then we end up with a 0 on the sulfur there.
如果我们来看看最后一个结构,在中间的原子是氮，我们同样可以计算出所有的形式电荷，而在这种情况下，氮为正一，碳为负二，而最后硫为零。
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So that's going to be the end of the exam 1 material, and then we'll move on to exam 2 material, which is kind of exciting, because we've been talking about just individual atoms and ions up to this point, and now we can talk about molecules, so we're going to start talking about bonding.
到此为止就是第一次考试的内容，接下来我们会开始讲第二次考试的内容，这些内容令人有点兴奋，因为我们一直都只是在讨论单个的原子,和离子到目前为止，而现在我们可以讨论分子了，要开始讨论成键的问题了。
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