Whereas in the linear case, I make it ten times bigger, it takes ten times longer to run. OK.

它要占用原来十倍的时间去运行，我一直在说还有一件事情没有讲，这是我要强调的最后一件事。

麻省理工公开课 - 计算机科学及编程导论课程节选

OK, in each case, what these things are doing, is they're doing, what sometimes gets referred to as operator overloading.

这将会是个默认的或者说是，通用的来比较对象是否相同的方法，好，在每个例子中，这些事情正在做的，就是,一些与操作符重载有关的东西。

麻省理工公开课 - 计算机科学及编程导论课程节选

So if delta v is negative, in this case delta v is negative, OK, delta v is negative, pressure is a positive number, negative times negative is positive, work is greater than zero.

也就是当活塞,压缩气体的时候，做的功是正的，按照这一规定,我们需要在这里，加上一个负号，这是习惯规定。

麻省理工公开课 - 热力学与动力学课程节选

OK, as I said, I want equality in the case of points to be, are the x- and y- coordinates the same?

好，正如我所说，我想要这个例子中的，点相等的意思是？

麻省理工公开课 - 计算机科学及编程导论课程节选

And the code over here says, OK gee, if I'm in the base case do something.

如果我属于基础事件就进行一些操作，而我不是，所以往下看这儿。

麻省理工公开课 - 计算机科学及编程导论课程节选

How long does it take me to find the k'th element? Linear. Because I've got to walk my way down it. OK? So in this case, you have linear access. Oh fudge knuckle.

线性的！因为我得从头,向下走一步步走,所以这里是线性访问，哦，有问题了吧。

麻省理工公开课 - 计算机科学及编程导论课程节选

The answer is I can't. OK, in the simple case of integers I can, but in the case of something more complex like faces or fingerprints or passwords for that matter, it's hard to design a hash function that has completely even distribution, meaning that it takes any input into exactly one output spot.

答案是我不能，好吧,在简单的整数的例子中,我可以做到，但是在一些更复杂的场景中,比如面部，指纹，密码相关的问题中，很难设计一个哈希函数具备完全平均的分配,也就是说，做到对任一输入，可以准确地得到相应的唯一输出,因此在一个哈希问题中。

麻省理工公开课 - 计算机科学及编程导论课程节选