• N But it's definitely not one and in fact it wasn't N in the case of Selection Sort because remember the algorithm we implemented on stage last week had me going back and forth across the stage selecting on iteration, the smallest person I can find, the smallest number and then putting them into place.

    但在选择排序中,肯定不会是1,也不是,注意,上周我们在这儿,实现的算法中,反复地,迭代进行选择,选出最小的数,然后将其放在合适的位置。

    哈佛公开课 - 计算机科学课程节选

  • If we can sort things, you know, we get this n log n behavior, and we got a n log n behavior overall. But can we actually do better in terms of searching.

    如果我们可以排序,如你所知,我们有n,log,n级别的算法,并且我有一个整体的n,log,n级别的算法,但是我们在搜索方面可以做的更好吗?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Like what the heck have we been spending our time for-- our time on with Bubble Sort and with Selection Sort and in fact there's plenty of other N squared sorts that we're not even gonna bother looking at.

    真见鬼,我们竟然在-,冒泡排序和选择排序上花时间,而事实上,还有很多我们根本都不想考虑的,复杂度为N平方的排序方法。

    哈佛公开课 - 计算机科学课程节选

  • If I'm using algorithm that I'm now calling merge sort, T the running time involved in sorting N elements, T of N, you know, is just the same as running the algorithm for the right half, plus what's this plus N come from?

    如果我用归并排序算法,对N个元素其运行时间,就等于此算法一半元素的运行时间,另一半的运行时间,再加上N,这个N是什么呢?

    哈佛公开课 - 计算机科学课程节选

  • It at least does corroborate the claim that merge sort N*log N as we argue intuitively is in fact, N log N in running time.

    但这至少证实了归并排序,的时间复杂度为。

    哈佛公开课 - 计算机科学课程节选

  • Now, it's kind of a cyclical argument here because how do you sort the left half of N elements?

    在这儿有点循环的意思,那么如何对N个元素中的左半部分进行排序呢?

    哈佛公开课 - 计算机科学课程节选

  • I know it's gonna take me a lot of work on the order of N squared steps to sort these things.

    要对它们排序就要进行大量的工作,大概需要N平方步。

    哈佛公开课 - 计算机科学课程节选

  • I can tell you how to sort N elements by saying in kind of a snide way.

    我可以告诉你一种方法,去对这N个元素进行排序。

    哈佛公开课 - 计算机科学课程节选

  • I could still do the linear case, which is order n or I could say, look, take the list, let's sort it and then search it. But in that case we said well to sort it was going to take n log n time, assuming I can do that.

    我仍然可以做O的线性搜索,或者也可以以这个列表为例,我们先将其进行排序,然后再进行查找,但是在这种情况下,要花费n,log,n的时间去对其进行排序。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Alright, you want me to sort N elements.

    既然要对N个元素排序。

    哈佛公开课 - 计算机科学课程节选

  • On the other hand, if I want to sort it first, OK, if I want to do sort and search, I want to sort it, it's going to take n log n time to sort it, and having done that, then I can search it in log n time.

    我先排序,好的,如果我想排序再搜索,我要排序,这需要花n,log,n时间排序,然后做完了,我们能花log,n时间搜索,啊,哪一种更好呢?恩,呵呵。

    麻省理工公开课 - 计算机科学及编程导论课程节选

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