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So, what we're saying is that we have n equals to 4, and m sub I being equal to negative 2.
我们说的是ｎ等于４,ｍｌ等于－２
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Negative 1 plus 0 should add up to negative 1, if in fact, we're correct for the c n anion.
负一加上零应该等于负一，如果是这样，我们对于氰离子的结果就是正确的。
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All the energies are negative because it is a bound system. I start up here with n equals one.
所有能量级都是负数，因为它是一个束缚系统,在这里我从n等于1讲起。
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If n is greater than zero, I decided I would say, "You picked a positive number, backslash n," so put the cursor on the next line, else if n was not less than zero, I say, "You picked a negative number, backslash n."
如果n比0大，我就决定来说：,“你选择了一个整数，反斜杠n“，所以你把光标,放在下一行，另外如果n不小于0，我说：,“你选择一个负数，反斜杠n“
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So, if we think about the second case here where we have c n minus, now we're talking about a molecule with a net charge of negative 1.
那么，如果我们考虑的是第二个例子,也就是氰离子，那么现在我们讨论的是一个净电荷量为负一的分子。
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n And these are known as anions. It has the n, which might conjure up negative, or anion and minus both have five letters.
这些就是负离子，有，能让我们想起，负，这个字，或者负离子和负号都是5个字母。
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PROFESSOR: OK. We can have n 4, l 3, and then, sure, we can have m sub l equal negative 2 if l equals 3 What's the second value of l that we can have?
教授：嗯，我们有ｎ４，ｌ３,然后我们有ｍｌ等于－２，如果ｌ等于３,ｌ可以有的第二个值是多少？
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So now we have that energy is equal to the negative of the Rydberg constant divided by n squared.
我们可以把能量方程大大简化,现在能量等于负的Rydberg常数除以n平方。
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So instead of being equal to negative z squared, now we're equal to negative z effective squared times r h all over n squared.
这里不再等于-z的平方，现在我们等于-有效的z的平方,乘以RH除以n的平方。
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And that's going to be equal to negative z effective squared times r h over n squared.
有效的z的平方,乘以RH除以n的平方。
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ml=-2 So let's say we have n equals 4, and n sub l equalling negative 2.
这里n等于。
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n l So negative e, which is sub n l, because it's a function of n and l in terms of quantum numbers.
也就是负的，E，下标是，因为它是一个,关于量子数，n，和，l，的函数。
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So we know that we can relate to z effective to the actual energy level of each of those orbitals, and we can do that using this equation here where it's negative z effective squared r h over n squared, we're going to see that again and again.
我们知道我们可以将有效电荷量与,每个轨道的实际能级联系起来，我们可以使用方程去解它,乘以RH除以n的平方,它等于负的有效电荷量的平方,我们将会一次又一次的看到它。
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So, it's negative Rydberg constant over n squared.
它等于负的Rydberg常数，除以n平方。
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We're going to get to more complicated atoms eventually where we're going to have more than one electron in it, but when we're talking about a single electron atom, we know that the binding energy is equal to the negative of the Rydberg constant over n squared, so it's only depends on n.
我们以后会讲到，更加复杂的情况,那时候,不只有一个原子，但当我们讲，单个原子的时候，我们知道结合能，等于,负的Rydberg常数,除以n平方，所以它仅仅由n决定的。
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We also know how to figure out the energy of this orbital, and we know how to figure out the energy using this formula here, which was the binding energy, -Rh which is negative r h, we can plug it in because n equals 1, so over 1 squared, and the actual energy is here.
我们知道如何算出,这个轨道的能级，而且我们知道如何,用这个公式,算出能量，也即是结合能，等于，我们把n等于1代进来，所以除以1的平方，这就是能量。
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