And we talked about the equation you can use for radial nodes last time, and that's just n minus 1 minus l.

我们讲过这个用于,计算径向节点的方程，也就是ｎ减去ｌ减去１

麻省理工公开课 - 化学原理课程节选

So, what we have left in our equation is only one part that n we haven't explained yet, and that is that n value.

现在方程里只剩下一个常数,我们还没有解释，这就是。

麻省理工公开课 - 化学原理课程节选

So it's a more specific version of the equation where we have the n final equal to 2.

当我们令n等于2时,使这个这个方程变成更具体的版本。

麻省理工公开课 - 化学原理课程节选

psi So we're going to for psi, and before that, we're going to figure out that instead of n just that one quantum number n, we're going to have a few other quantum numbers that fall out of solving the Schrodinger equation for what psi is.

我们要讲到，但在这之前，我们已经知道了,主量子数，现在我们需要知道，其他一些,解psi的薛定谔方程,所需要的量子数。

麻省理工公开课 - 化学原理课程节选

l So, if we're talking about a 4 p orbital, and our equation is n minus 1 minus l, the principle quantum number is 1 4, 1 is 1 -- what is l for a p orbital?

我们方程是n减去1减去，主量子数是，4，1是1，--p轨道的l是多少？,学生：

麻省理工公开课 - 化学原理课程节选

So we know that we can relate to z effective to the actual energy level of each of those orbitals, and we can do that using this equation here where it's negative z effective squared r h over n squared, we're going to see that again and again.

我们知道我们可以将有效电荷量与,每个轨道的实际能级联系起来，我们可以使用方程去解它,乘以RH除以n的平方,它等于负的有效电荷量的平方,我们将会一次又一次的看到它。

麻省理工公开课 - 化学原理课程节选

So, if we just rearrange this equation, what we find is that z effective is equal to n squared times the ionization energy, IE all over the Rydberg constant and the square root of this.

我们可以发现有效的z等于n的平凡，乘以电离能除以里德堡常数,这些所有再开方，所以等于n乘以,除以RH整体的平方根。

麻省理工公开课 - 化学原理课程节选