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(Test) The U.N.Secretary-General says he is "optimistic" a climate-change agreement can be reached in Copenhagen that will include specific recommendations on key elements that will take effect immediately.
VOA: standard.2009.12.09
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If n = 1, x/n can take on only two values: 0 or 1.
当n=1时,x/n的值只可能等于0和1
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And we can calculate that with the formula that we used, which was just n minus l minus 1 equals the number of nodes.
这个我们可以用我们以前用过的那个公式来计算，也就是节点数等于ｎ减去ｌ减去１
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"This is one of the clearest calls repeatedly rendered to the government of Sri Lanka - that the U.N.be allowed to access the area so we can assess independently the situation of civilians,"
VOA: standard.2009.05.11
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So if I start off with a list of length n, how many times can I divide it by 2, until I get to something no more than two left?
我能够除以多少次2呢？,直到我得到的长度不超过2么？,对数次，对吧？就像刚才那位同学说的那样？
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For the U.N.to keep urging that peace be created first before a U.N.peacekeeping force can be sent continues to deny the Somali people badly-needed international forces to assist in the stabilization of that country,".
VOA: standard.2009.06.26
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So, the optimal thing to do if you live in a world like this n is to get n as large possible and you can reduce the standard deviation of the portfolio very much and there's no cost in terms of expected return.
如果现实中也这样简单的话,那么你就尽量增大,这样就能让投资组合的标准差,就会大大降低,从预期收益率的角度来看,这样做的成本是零。
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N Well, here is a list of size N. How many times can you divide a list of size N by 2, right?
这是一个大小为N的列表，将一个大小为,的列表除以2需要几次呢？
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RT So it's delta u plus RT, we can say T1 is the n temperature we've used here, delta n of the gas.
所以它应该是ΔU加,我们可以在这里用T1，气体的Δ
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N And we can keep doing"T","A","N", ? and I think you see where it is going.
然后接着移动字母，T，A，和，我想大家应该知道后面是哪些字母了吧。
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N You can even abbreviate and put Y or N.
甚至可以缩写Y或。
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And if you put this in the well-ventilated area, if you prepare this outside, the h c n gas will actually be released into the air, so you're safe, you can eat it later.
而如果你把它们放在通风良好的地方，在室外处理，那么氰化氢气体,将会被释放到空气中，这样你就安全了，过后就可以吃了。
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And we talked about the equation you can use for radial nodes last time, and that's just n minus 1 minus l.
我们讲过这个用于,计算径向节点的方程，也就是ｎ减去ｌ减去１
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If we have n equals 4, what is the highest value of l that we can have?
如果ｎ等于４,ｌ的最大值是多少？
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So let's actually just simplify this to the other version of the Rydberg constant, since we can use that here.
除以n初始的平方，我们把它简化成,另一种形式的Rydberg常数。
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How many times you can divide N by 2 before you get down to 1?
在得到1之前需要将N除以2做几次呢？
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So we know that we're in the n equals 5 state, so we can find what the binding energy is here.
我们知道,我们在n等于5的态，我们可以找到结合能是多少。
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If we can sort things, you know, we get this n log n behavior, and we got a n log n behavior overall. But can we actually do better in terms of searching.
如果我们可以排序，如你所知，我们有n，log，n级别的算法，并且我有一个整体的n，log，n级别的算法,但是我们在搜索方面可以做的更好吗？
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PROFESSOR: Good. So, it's going to be in 3, because that's the shortest energy difference we can have, 3 those 2 are inversely related, so it must be n equals 3.
教授：好，是3，因为它的能量差最小，红色的是我们能看到的，所以一定是n等于。
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So, our next level up that we can go is going to be the n equals 2 energy level, but we also have an l and an m value, 0 so our lowest l is going to be a there.
所以下一个能量,是n等于2的能级，但我们还有l和m的值，所以我们最低的l等于。
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And the last thing we can think about is how do we name this n h bond, and again, we just name it based on it symmetry.
最后我们要讨论的是,如何命名这个NH键，同样，我们基于它的对称性命名它。
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And, in fact, it can't even reach n, because then we would have no potential energy at all in our electron, which is not correct.
事实上，它连n都达不到，因为如果那样的话,电子就没有势能了，这是不可能的。
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So for sodium, again, we can write n e 3s1 and then 3 s 1.
对于钠，再一次,我们可以写Ne然后。
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So if we go to the ground state, what you see is we're at that lowest energy level, and we only have one possibility for an orbital, because when n equals 1, that's all we can do.
如果我们在基态上，你可以看到，我们在能量最低的态上，只有一种，可能的轨道，因为n等于1，只有这种可能。
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So if we say that we have a 2 p orbital here, that means that we can have 2 how many different complete orbitals have a 2 for an n, and a p as its l value? three.
如果我们说这里有一个“2p“轨道，那就意味着我们有,多少完全不同的轨道对于n有一个,而且对于l值有一个p？3个。
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And we can generalize to figure out, based on any principle quantum number n, how many orbitals we have of the same energy, n and what we can say is that for any shell n, there are n squared degenerate orbitals.
我们可以总结出来，在，主量子数为n的情况下，同一个能量上，有多少个轨道，我们可以说，对任何壳层，有n平方个简并轨道。
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I could still do the linear case, which is order n or I could say, look, take the list, let's sort it and then search it. But in that case we said well to sort it was going to take n log n time, assuming I can do that.
我仍然可以做O的线性搜索,或者也可以以这个列表为例，我们先将其进行排序,然后再进行查找，但是在这种情况下,要花费n，log，n的时间去对其进行排序。
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On the other hand, if I want to sort it first, OK, if I want to do sort and search, I want to sort it, it's going to take n log n time to sort it, and having done that, then I can search it in log n time.
我先排序，好的，如果我想排序再搜索，我要排序，这需要花n，log，n时间排序，然后做完了，我们能花log，n时间搜索,啊，哪一种更好呢？恩，呵呵。
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PROFESSOR: OK. We can have n 4, l 3, and then, sure, we can have m sub l equal negative 2 if l equals 3 What's the second value of l that we can have?
教授：嗯，我们有ｎ４，ｌ３,然后我们有ｍｌ等于－２，如果ｌ等于３,ｌ可以有的第二个值是多少？
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The other thing is that we can re-write our h c n in terms of bonds.
还有一件事是我们可以用键的形式来表示氰化氢。
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