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PROFESSOR: OK. We can have n 4, l 3, and then, sure, we can have m sub l equal negative 2 if l equals 3 What's the second value of l that we can have?
教授：嗯，我们有ｎ４，ｌ３,然后我们有ｍｌ等于－２，如果ｌ等于３,ｌ可以有的第二个值是多少？
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-- Else if n is greater than 4 and n is less than 6 -- 7 let's call it medium -- else if n is greater than or equal to 7, -- less than or equal to 10 -- let's call it "big" -- and if the user typed in zero or negative 10 or 20 or whatever, let's just use the all-inclusive else block and just say, "You picked an invalid number."
否则如果n大于4，并且n小于-,我们叫它为中间数--否则如果n大于等于，小于等于10--我们叫它为“大数“,如果用户键入了0或者-10或20或其它的，让我们用一个广泛的else子句，只需要说，“你选了一个非法的数字“
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So, what we're saying is that we have n equals to 4, and m sub I being equal to negative 2.
我们说的是ｎ等于４,ｍｌ等于－２
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One over two squared minus one over n squared 3 4 5 where n takes values three, four, five, six.
除以，2，的平方再减去1除以n的平方,将n赋值为。
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Log n Log n, because at each stage I'm cutting the problem in half. So I start off with n then it's n n/2 n/4 n/8 over two n over four n over eight.
因为总共有多少层？,因为在每一层，我都是把问题分解成两半,因此以n开始，然后是。
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Then, if n = 100--now I'm going to label this x differently, I'm now going to show the normal bell-shaped curve and I'm going to do this from 0 to .4.
如果n=100,现在我得重新标x值,我现在要画正态分布的钟形曲线了,在这儿用0到0.4
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So we have 4 plus 5, but we're actually not done yet, because it's c n minus, so if we have minus, we actually have an extra electron in our molecule.
我们有四个加上五个，但是我们实际上还没做完，因为这是个负离子，所以如果我们有这个负号，那么我们的分子实际上还有一个额外的电子。
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If we have n equals 4, what is the highest value of l that we can have?
如果ｎ等于４,ｌ的最大值是多少？
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When we talk about the n equals 2 state, we now have 2 squared or 4 degenerate same energy orbitals, and those are the 2 s orbital.
当考虑n等于2的态时，我们有2的平方,或者4个简并能量的轨道，它们是2s轨道。
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If I look at something that goes as n squared, if this is the edge of the nucleus here and if this is r1, 4 it says when n goes to two the radius goes to four.
如果在原子核外侧,我们发现某一半径和n的平方成正比，也就是说当n为2时半径等于。
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They're not going to want to add on another electron, because then it'll have to jump a very large energy level go from n equals 2, to n equals 3, and n equals 4, and so on.
它们不愿意增加另外一个电子，因为这会让它们跳到一个非常高的能级上去,依次是，n，等于，2，3，4，等等。
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So the take away is that if the user actually gives me two or three or four or whatever, this is this expression "is n less than 1" is going to evaluate to false if it's actually two or three or four or whatever.
所以先不管用户实际上给我,3，4还是其他数，这个表达式,“是否n小于1“将被评估为错误的,如果输入额是2，3，4或其它的数。
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Up here I have n over two operations of size two. Up here I've got n over four operations of size four.
最下面有n个规模为1的操作,接着上面有n/2个规模为2的操作,再上面有n/4个规模为4的操作。
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So, the third excited state, is n equal to 4, because n equals 2 is first excited, 3 is second excited, 4 is third excited state.
因为n等于2是第一激发态,等于3是第二激发态。
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ml=-2 So let's say we have n equals 4, and n sub l equalling negative 2.
这里n等于。
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And in this case, we go from 8 to 4 to 2 to 1 three times and then on each iteration of this algorithm, each pass across the board I'm touching N numbers, so that means I'm doing N things, log N times.
在这个例子中，我们从8得到4，到2，再到1，是3次,在这个算法的每次迭代中，每一趟我都会操作N个数，也就是所我每次要做N步操作，一共要做，log，N，次。
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l So, if we're talking about a 4 p orbital, and our equation is n minus 1 minus l, the principle quantum number is 1 4, 1 is 1 -- what is l for a p orbital?
我们方程是n减去1减去，主量子数是，4，1是1，--p轨道的l是多少？,学生：
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So the key word here is that we asked you to identify the third excited state. So, what white is n equal 4 Ok to for the third excited state? 4 OK.
这里的关键的地方是我,要你们找到第三激发态,第三激发态的n等于多少？
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We're getting further away from the nucleus because we're jumping, for example, from the n equals 2 to the n equals 3 shell, or from the n equals 3 to the n equals 4 shell.
我们将会离原子核越来越远,因为我们在跃迁，比如从，n，等于，2，的壳层到n等于，3，的壳层，或者从，n，等于，3，的壳层到n等于，4，的壳层。
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N 6 Sixteen, so that's 16 times log base 2 of 16 and though I'm writing small here, log base 2 of 16, 16 this gives me 4 'cause 2 to the 4 equals 16.
是多少呢？，Well，，N，is，what？,16，那就是16乘以以2为底16的对数6,在这儿我将2写小一些，以2为底16的对数是4，因为2^4等于。
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So int n just gives me four bytes for an int, but it doesn't put anything there yet.
所以int，n只是给我们分配了4个字节，但是它没有放任何东西在那里。
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