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VOA: standard.2010.01.14

Negative 1 plus 0 should add up to negative 1, if in fact, we're correct for the c n anion.

负一加上零应该等于负一，如果是这样，我们对于氰离子的结果就是正确的。

麻省理工公开课 - 化学原理课程节选

f=0 I would write f of x is in big Oh of n squared.

我写下了。

麻省理工公开课 - 计算机科学及编程导论课程节选

And unlike n, l can start all the way down at 0, and it increases by integer value, so we go 1, 2, 3, and all the way up.

不像n，l可以从0开始取，然后每次增加一个整数，所以我们可以去1，2，3，一直下去。

麻省理工公开课 - 化学原理课程节选

So when we count, generally, again, we start from zero, we go to N minus 1.

当我们计数时，一般的，再次强调，我们从0开始，到N-1结束。

哈佛公开课 - 计算机科学课程节选

If n = 1, x/n can take on only two values: 0 or 1.

当n=1时,x/n的值只可能等于0和1

耶鲁公开课 - 金融市场课程节选

So, our next level up that we can go is going to be the n equals 2 energy level, but we also have an l and an m value, 0 so our lowest l is going to be a there.

所以下一个能量,是n等于2的能级，但我们还有l和m的值，所以我们最低的l等于。

麻省理工公开课 - 化学原理课程节选

to the n, every value in the 1 bit vector we looked at last time is either 0 or 1. So it's a binary n number of n bits, 2 to the n.

从2到n，我们上次看到的,位向量的每个值不是0就是,所以它是n，比特的二进制数,从2到。

麻省理工公开课 - 计算机科学及编程导论课程节选

And what you can see is that 0 for any n that has an l equals 0, you can see here how there's only one possibility for and orbital description, and that's why we don't need to include the m m when we're talking about and s orbital.

你们可以看到,对于任何n，如果l等于，你们从这里可以看到，只有，一种,可能的轨道描述，所以,当讨论s轨道的时候,不需要考虑。

麻省理工公开课 - 化学原理课程节选

Then, if n = 100--now I'm going to label this x differently, I'm now going to show the normal bell-shaped curve and I'm going to do this from 0 to .4.

如果n=100,现在我得重新标x值,我现在要画正态分布的钟形曲线了,在这儿用0到0.4

耶鲁公开课 - 金融市场课程节选

If n is greater than zero, I decided I would say, "You picked a positive number, backslash n," so put the cursor on the next line, else if n was not less than zero, I say, "You picked a negative number, backslash n."

如果n比0大，我就决定来说：,“你选择了一个整数，反斜杠n“，所以你把光标,放在下一行，另外如果n不小于0，我说：,“你选择一个负数，反斜杠n“

哈佛公开课 - 计算机科学课程节选

Right. N is over here for counting from zero.

对的，从0开始计数，N到了这边。

哈佛公开课 - 计算机科学课程节选

Well, this question mark becomes an O, this question mark becomes an O, and then the loop terminates 0 1 2 because it's iterating from zero to N so that's zero, 1, 2 and the length of the string is 3 so the loop terminates, but I remember that I needed to have this special sentinel value so I'm just going to put it there manually.

嗯，这个问号变成了，这个问号变成了0，然后循环结束了,以为迭代从0到N，那就是，字符串的长度是3，然后循环就结束了，但是我记得我需要这个特殊的标记值,所以需要手动的加上它。

哈佛公开课 - 计算机科学课程节选