Suppose f of x, y, z equals k1, that is my equation, s1 and it gives me a solution s1.

假设我的方程是这样，然后给出了一个解。

麻省理工公开课 - 固态化学导论课程节选

printf I have my includes, standard IO's; so I can use print F, but then I had this thing called a prototype.

我包含了标准输入输出文件，所以我可以使用，然后我有这个原型。

哈佛公开课 - 计算机科学课程节选

That's true, but especially because of my parenthesization 32 over here, because I'm saying, "Do f minus 32, but then multiply it by the division on the left."

是那样的，但是特别地，因为我这里加上了括号,因为我指明，“f减去，然后它乘以左边的那个除法的结果“

哈佛公开课 - 计算机科学课程节选