You've got to juggle the two equations, multiply that by 4, multiply that by 3, add and subtract and so on.

同时处理这两个方程,这个两边乘以4,另一个两边乘以3,将两方程相加或相减求出答案

耶鲁公开课 - 基础物理课程节选

And what I am going to do is say start with this ion, add up the energy associated with the interactions between that ion and everybody else in the row and then multiply it by Avogadro's number, because that is the number of atoms there are in a row.

接下来我要从这一离子开始，加上相互作用的能量，也就是这一离子,和其它所有在这一行的离子之间的能量,再乘以阿伏加德罗常数，因为这是在一行的原子的数量。

麻省理工公开课 - 固态化学导论课程节选

You can take this vector, multiply it by one number, take that vector, multiply it by another number, add the two of them.

比如将这个矢量,乘上一个数,然后将另一个矢量,乘上另外一个数,把这两个矢量相加

耶鲁公开课 - 基础物理课程节选

OK, I can certainly print out strings, but I can actually add strings together, and just as you saw, I can multiply strings, you can kind of guess what this is going to do.

当然我可以显示字符串，但是其实我还可以令字符串相加，如你所见到的，我可以令字符串相乘，你们可以想想答案是什么。

麻省理工公开课 - 计算机科学及编程导论课程节选

What I am going to do now is I am going to multiply by N Avogadro and then add Born repulsion.

我接下来要做的是,将其乘以阿伏加德罗常数,再加入Born的排斥作用。

麻省理工公开课 - 固态化学导论课程节选

To get any location in memory, to get to any value of the list, I simply have to say which element do I want to get, I know that these things are stored in a particular size multiply that index by 4, add it to start, and then it's in a constant amount of time I can go to that location and get out the cell.

取得列表中的任何一个值,简单说来，想要取得列表中的任何元素,我知道这些元素存在特定的大小中,把下标乘以4，加到start上,然后定位到内存单元，并取出值就是固定的时间了,好的，如果元素以固定大小存储。

麻省理工公开课 - 计算机科学及编程导论课程节选