All right, so the bonding order, you're correct, should be 2, if we subtract the number of bonding minus anti-bonding electrons and take that in 1/2.

好，你们是对的，键序为，如果我们用成键数,减去反键数除以2。

麻省理工公开课 - 化学原理课程节选

And then if we think about 3 s, 0 we want to start with 3, we subtract 1, again l is equal to 0, so minus and we have two radial nodes.

我们从3开始，减去，同样的l等于，所以减去0，我们有两个节点，这应该。

麻省理工公开课 - 化学原理课程节选