• Getting a grade like a B-plus or a C-minus adds or subtracts a few tenths of a point.

    VOA: special.2009.03.05

  • So this one is spin-up plus a half, this is spin-down minus a half.

    所以自旋向上是正二分之一,而自旋向下是负二分之一。

    麻省理工公开课 - 固态化学导论课程节选

  • So for the bond order we want to take 1/2 of the total number of bonding electrons, so that's going to be 4 minus anti-bonding is 4, so we end up getting a bond order that's equal to 0.

    键序等于1/2乘以,总的成键电子数,也就是4,减去反键电子数,也就是4。,所以最后得到键序为0。

    麻省理工公开课 - 化学原理课程节选

  • Everything inside the parenthesis is positive, so minus a positive number.

    而其中间的一切,也是正数,所以正数的相反是负数。

    麻省理工公开课 - 固态化学导论课程节选

  • And then I'll create this function, d1 this distribution d 1, which will, whenever I call it, give me a random, a uniformly selected value between minus and plus volatility.

    然后我会创建这个函数,这个概率分布,每次我调用这个函数的时候,他会给我返回一个随机的,按照均匀分布,从正负浮动值之间选择的值。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • This has a minus and that doesn't have a minus.

    这里有一个负号而那里没有

    耶鲁公开课 - 基础物理课程节选

  • So basically what I'm going to do here is I'm going to set my price to equal his price, minus a little bit, I'll just undercut him a little bit and by just undercutting him a little bit, I'm going to get the whole of the market and I'll make as much money as I can on those sales.

    所以基本上我要做的是,设定我的价格等于他的价格,减去一点点,我的价格将仅仅比他的低一点点,并且通过比他的价格低一点点,我将占领整个市场,那些销售带给我尽可能多的钱

    耶鲁公开课 - 博弈论课程节选

  • b It's RT over molar volume minus b minus a over molar volume V squared.

    它等于RT除以摩尔体积V杠减去,再减去a除以摩尔体积的V杠平方。

    麻省理工公开课 - 热力学与动力学课程节选

  • Anything where you're actually keeping track of something like a score that's having a variable that you increment -- plus, plus, or decrement, minus, minus, using the appropriate puzzle piece could certainly be compelling.

    你需要保存像分数这样的事物时,你就需要一个变量,它可以自加,++,或者自减,要使用正确的拼图。

    哈佛公开课 - 计算机科学课程节选

  • So you buy it at a discount and the return you get is of course a hundred minus--the return you get is the discount.

    所以以折价买入,并且回报等于,100减去,回报等于折扣差价

    耶鲁公开课 - 金融市场课程节选

  • For the carbon, we start with 4 valence electrons, we have 0 lone pair electrons minus 4, and we end up with a formal charge of 0.

    对于碳,我们从四个价电子开始,我们有零个孤对电子,再减去四,最终我们有零个形式电荷。

    麻省理工公开课 - 化学原理课程节选

  • So, if we think about the second case here where we have c n minus, now we're talking about a molecule with a net charge of negative 1.

    那么,如果我们考虑的是第二个例子,也就是氰离子,那么现在我们讨论的是一个净电荷量为负一的分子。

    麻省理工公开课 - 化学原理课程节选

  • And that makes sense, too, because the positive three pulling on minus one has a tighter binding energy than positive one pulling on minus one.

    而这也是有意义的,因为+3和-1的相互吸引,产生了比+1和-1的吸引,更强的能量。

    麻省理工公开课 - 固态化学导论课程节选

  • It bears a negative charge and the value of minus 1.6 times 10 to the 19 coulombs.

    电子是带负电荷的,并且,负电的值为1。6乘以10到19,库伦。

    麻省理工公开课 - 固态化学导论课程节选

  • Once you've got that, you can do minus 7 times a vector Just take the vector, multiply it by Pi and flip it over.

    明白这点之后,你就可以计算-7乘以矢量,只需用 π 去乘以那个矢量,然后将其方向调转

    耶鲁公开课 - 基础物理课程节选

  • They would have won five bucks minus five cents for a total of four ninety-five.

    他将得到5美元减去5美分,就是4美元95美分

    耶鲁公开课 - 博弈论课程节选

  • pV=RT p plus a over v bar squared times v bar minus b equals r t. All right if you take a equal to zero, these are the two parameters, a and b. If you take those two equal to zero you have p v is equal to r t.

    我们就回到,也就是理想气体,状态方程,下面我们来看看,这个方程。

    麻省理工公开课 - 热力学与动力学课程节选

  • So we can have, if we have the final quantum number m equal plus 1 or minus 1, we're dealing with a p x or a p y orbital.

    所以如果我们有,磁量子数m等于正负1,我们讨论的就是px或者py轨道。

    麻省理工公开课 - 化学原理课程节选

  • So, let's try another example here, and let's try a case now where instead of dealing with a neutral molecule we have an ion, so we have c n minus.

    那么,让我们来试一下另外一个例子,这次不是一个中性原子,而是一个离子,氰离子。

    麻省理工公开课 - 化学原理课程节选

  • So, you should know that there's four radial nodes, right, we have 5 minus 1 minus l -- is there a question?

    你们要记住这里有四个节点,对吧,5减去1减去l,有问题吗?

    麻省理工公开课 - 化学原理课程节选

  • Well, I'll give you a hint, it starts with a minus. What next?

    好的,我会给你一个提示,第一个数是-,接下来呢?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So we know that it's 1, because we have 1, 2, 3, 4 bonding, minus 2 anti-bonding, and 1/2 of that is a bond order of 1.

    我们知道它是,因为我们有1,2,3,4个成键,减去2个反键,它的一半就是键序为1。

    麻省理工公开课 - 化学原理课程节选

  • It is of opposite charge and it exerts an influence, only that is minus to plus so that is going to give me a minus term here.

    它具有相反的电性,所以它也会有影响,只有这个负值相对正值来说会起到减少的作用,所以这里将会引入一个负值的量。

    麻省理工公开课 - 固态化学导论课程节选

  • 0 And it has a mass of 9.11 times 10 to the minus 31 kilograms The charge compensation comes out of the nucleus with the proton and it is positive 1.6 times 10 to the minus 19 coulombs.

    它的质量是9。11乘以0,到负31千克,电荷补偿来自于,有质子的原子核,它是+1。6*10^库伦。

    麻省理工公开课 - 固态化学导论课程节选

  • If I look for, say, minus 1, you might go, gee, wait a minute, if I was just doing linear search, I would've known right away that minus one wasn't in this list, because it's sorted and it's smaller than the first elements.

    如果我要查找-1,你可能要怒了,呵呵,等一等,如果我用的是线性查找,我不会知道-1不在这个列表中,但是列表是排好序的,1又比第一个元素小。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Multiply a by a to the b minus 1.

    这很不错对不对?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • We have the minus because we're adding a negative charge from the electron.

    有这个负号的原因是,我们得到一个电子后增加了一个单位负电荷。

    麻省理工公开课 - 化学原理课程节选

  • And I'll just put a minus indicating I'm done.

    我会放一个-在这里,表示我没有物品可选了。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • No, here both are plus, but this one has a minus.

    不对,这里都是加号,但这有个负号

    耶鲁公开课 - 基础物理课程节选

  • If we look at our last structure here where we have nitrogen the middle, we can also figure out all those formal charges, and in this case we have plus 1 on the nitrogen, we have minus 2 on the carbon, and then we end up with a 0 on the sulfur there.

    如果我们来看看最后一个结构,在中间的原子是氮,我们同样可以计算出所有的形式电荷,而在这种情况下,氮为正一,碳为负二,而最后硫为零。

    麻省理工公开课 - 化学原理课程节选

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