• Constant. Ooh, constant says, no matter what the length of the list is, I'm going to take the same amount of time.

    这个算法用的时间是相同的,我不这么认为,如果我们创建一个十倍于以前大小的数组。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Remember we said we design lists so that the access, no matter where it was on the list was of constant time.

    记住我们说过我们创建了,一个列表它就是这么访问的,无论它在列表的哪个位置。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Okay, so 1 is a viable answer in some contacts that needs constant time, the same amount of time no matter what.

    在需要常量时间的情况下,答案是1,不管怎样,总时间是,相同的。

    哈佛公开课 - 计算机科学课程节选

  • In other words, the order of taking the derivatives with respect to pressure and temperature doesn't matter And what this will show is that dS/dp dS/dp at constant temperature, here we saw how entropy varies with volume, this is going to show us how it varies with pressure.

    换句话说,对温度和压强的求导顺序无关紧要,结果会表明,恒定温度下的,对应我们上面看到的,熵如何随着体积变化,这个式子告诉我们,熵如何随着压强变化。

    麻省理工公开课 - 热力学与动力学课程节选

  • So that should mean that the energy that's transferred to the electron should be greater, but that's not what you saw at all, and what you saw is that if you kept the frequency constant there was absolutely no change in the kinetic energy of the electrons, no matter how high up you had the intensity of the light go.

    所以这意味着转移到电子,上的能量也越大,但这并不是,我们观测到的现象,我们所看到的是,如果固定光的频率不变,不管光强如何变化,电子的动能没有任何变化。

    麻省理工公开课 - 化学原理课程节选

  • It grows as b. The 3 doesn't matter, it's just a constant, it's growing linearly.

    它按b来增长,3只是个常量,3没有作用,答案是线性增长的。

    麻省理工公开课 - 计算机科学及编程导论课程节选

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