O.K. But don't you be thinking that I'm goingto be calling you "sir."

VOA: standard.other

Why didn't they keep right on going with G, H, I, J, K, L, M, N, O, P?

为什么他们不接着写下去呢,按照字母表

耶鲁公开课 - 聆听音乐课程节选

Now I'm in better shape, right? Especially for really large n or for a lot of k, because now in general, this is going to be smaller than that.

很大的k也大的情况,因为这样这就比这个小了,这种情况是分摊。

麻省理工公开课 - 计算机科学及编程导论课程节选

No problem. Got to go.I'm double-parked. O.K. Thanks.

VOA: standard.other

The classic experiment that demonstrated anchoring was Kahneman and Tversky--I'm writing K&T -in a wheel of fortune experiment, which they did in 1974.

一个阐述锚定效应的经典实验是,卡尼曼和特维斯基...我用K&T来表示,他们在1974年做了幸运轮盘实验

耶鲁公开课 - 金融市场课程节选

Ugh. I'm O.K., Forrest.

VOA: standard.other

Mathematically complete problem is that you can find the function x of t by saying that the second derivative of the function is equal to -k over m times the function.

这个数学问题就是,你可以求出函数 x,只要令函数的二阶导数,等于 -k 除以 m 再乘以函数

耶鲁公开课 - 基础物理课程节选

I'm O.K. I'm fine.

VOA: standard.other

k * n m plus k all times log n is in general going to be much better than k times n.

在普遍情况下要远远好于,实际情况要取决于n和k的取值。

麻省理工公开课 - 计算机科学及编程导论课程节选

Bubba. I'm O.K., Forrest.

VOA: standard.other

So I'm done when b minus k equals 1, or k equals b minus 1.

因此b-k=1或k-b=1的时候，我就可以停下来了。

麻省理工公开课 - 计算机科学及编程导论课程节选

I'm O.K.

VOA: standard.other

Yeah. You're jumping slightly ahead of me, but basically, I'm done when this is equal to 1 right? Because I get down to the base case, so I'm done when b u is over 2 to the k is equal to 1, and you're absolutely right, that's when k is log base 2 of b.

因为这就是最基本的情况了，因此当b/2的k次方等于1的时候就停止了1,你说的太对了，就是k等于b的以2为底的对数的时候,你们都坐的挺靠后的啊，我不知道是不是我讲的不太明白？

麻省理工公开课 - 计算机科学及编程导论课程节选