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Let's test it in all possible combinations of x and y and see if we get the right answer.
来测试并看看,返回的结果正确不正确。
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So let's do c p 1 dot y, c p 2 dot y.
这不太好因为，两个地方的值都是一样的，对不对？
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Y Why don't I say int temp gets X. Let's say Y oh, sorry, X gets Y and then Y gets temp, this 2 would fail.
为什么我不说明，int，temp，=，X，让我们说明,哦，对不起，X=Y，然后，Y=temp，这两行将失败的。
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So let's look at the first case 2px where we have either the 2 p x or 2 p y type of orbitals that we're combining.
让我们看看第一个情形,我们要组合,或者2py轨道。
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So let's think about a particular consumer, so suppose this consumer is here, at point Y say.
让我们来考察一个特定的消费者,假设这个消费者在这,在Y点
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And that's the following. Let's take a particle that is moving in the x-y plane, so that at one instance-- sorry, let me change this graph-- is here--oh, this is bad.
接下来,我们来看一个物体,在 x-y 平面内运动,在这个例子中,对不起,我要重画一下这个图,在这里,这画得不好
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Let's actually screw this up and let's actually say, hmm, how about *y?
我把这个搞砸,我指明，嗯，*y，怎么样？
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Well let's look at the consumer at point Y.
我们来看一下在Y点的消费者
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3 Let's take y, change it to thirteen, let's run it, hmm.
把y赋值为，试着运行下程序，嗯。
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STUDENT: Let me compare y to Yeah, it's not doing all of the comparisons.
学生：让我把y和【不可闻的声音】做比较,对了，它并没有对所有的情况作比较。
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How would we go about, I mean I don't want to do it because I'll probably get it wrong, but if I wanted to solve out for this X and the Y, since this is a QR class, let's just talk about it a second.
我们怎么解呢,我的意思是我现在不会去计算,因为我可能会算错,但是如果你真的很想解出X和Y的值,介于这是一节需要快速反应的课,那我们花些时间来探讨一下吧
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