We want to integrate. So let's take the integral of both sides, going from the initial point to the final point.

分别从初态,到末态做积分，消去微分。

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Let's multiply both sides by 2, I'll get 2q1* is equal to a - c over b - q1*.

等式两边同时乘以2,得到,2q1*=/b-q1

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