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So finger-pointing at the start of each list, 6 is indeed less than 8 so I'm gonna write it down first.
手指指向列表的开始，6肯定比,8小，我先把它写下来。
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Also H&M is good or Forever 21, if you want less expensive clothes.
&M和Forever21价格不贵，也不错。
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However, what I'm saying is that it's important, not less important to focus on questions when it comes to education.
但是，我所说的是当提到教育时，关注问题很重要，而不是较不重要。
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OK? And in fact, if you look at the code up here, and it's on your handout, the very first one, x 1, right here- if I could ask you to look at it-- is a piece of code to do it. And I'm less interested in the code than how we're going to analyze it, but let's look at it for a second.
实际上，如果你看看,你们课堂发的材料上面的代码，第一页上的，就是那-,大家请看看实现的这一部分代码,我不太关心,我们会怎么解释这个代码,首先让我们先看看。
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Revenues minus costs makes profits, and again, for those of you who are less familiar with economics, I'm hoping this is not really too hard but you can read up on it.
收入减去成本就是利润,对经济学不太了解的同学,我觉得这个很简单,你们都能听懂吧
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But what's even worse is I'm going to get even less than the average amount of life.
但更糟糕的是,我活得比平均寿命还要短。
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The end test-- and I've got the wrong glasses on but it's up here, where I'm looking to see, is last minus first less than or equal to 2?
最后一次比较，我看错了,在上面，last减去first是不是小于2呢？,好的，既然我得到了一个？
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I can either look at my flow chart, or I can look at the code. If I look at the flow chart, it says, I'm at this point. Look at ANS squared. Is it less than or equal to-- sorry, first of all, 0 ANS squared is 0, is it less than or equal to x, yes.
我可以看流程图也可以看我的代码,如果我看流程图的话，流程图这么说的，在这一点，看看ANS的平方,看是不是小于等于-对不起，首先，ANS的平方是。
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Because what I want to do is, 01 say if self dot price is less than 0.01, 0 I'm going to set it to 0, just keep it there.
因为我想要做的是，比方说如果self。price小于0。,我就把它的值设为，然后放在那。
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I'm doing a test there to say, x if the string x is less than the value of b, and x does not appear before b as strings, then I was going to do, oh, a couple of things, because they're at the same block level.
我正在做一个测试来看看，字符串,是不是小于b的值，而且x不在b之前作为字符串出现，如果是真的话我就要做，一系列的操作，因为他们是在同一个块等级上。
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It would be nice if it was less than linear, but linear is nice because then I'm going to get that n log in kind of behavior.
那么就是一个不错的算法，但是线性方案也是很好的,因为我需要做n次的log级的行为。
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It says, right. If j is-- well it says until j is at the less than the length of l-- it says, if min value is bigger than the thing I'm looking at I'm going to do something, all right?
只要j比长度l小,如果MinVal比我要找到元素大，我就要做些什么了,我们来遍历？
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