"That's kind of fun!" "What's your name?" "Broklin,B-R-O-K-L-I-N."

VOA: special.2010.04.30

And if I pull it out one more level, 12k it's 12 plus 12 plus t of b over 8, 12 k because I'll have 12 of those to add up, plus t of b over 2 to the k.

总结一下也就是说，在k步以后，总步数应该是，那这种情况什么时候才能停止呢？,才能到达最基本的情况呢？

麻省理工公开课 - 计算机科学及编程导论课程节选

If I reduce that it would be 3 plus t of b minus 3, so in general 3*k+t this is 3 k plus t of b minus k. OK.

把b减去一个,在外面加个3就可以了,因此也就是。

麻省理工公开课 - 计算机科学及编程导论课程节选

and Gennadi Vasilenko, a former K.G.B.officer.

VOA: standard.2010.07.09

So I'm done when b minus k equals 1, or k equals b minus 1.

因此b-k=1或k-b=1的时候，我就可以停下来了。

麻省理工公开课 - 计算机科学及编程导论课程节选

Yeah. Actually, I think I want b minus k equal to 1. Right?

对，实际上，当b-k=1的时候就该停下来了对不对？

麻省理工公开课 - 计算机科学及编程导论课程节选

Yeah. You're jumping slightly ahead of me, but basically, I'm done when this is equal to 1 right? Because I get down to the base case, so I'm done when b u is over 2 to the k is equal to 1, and you're absolutely right, that's when k is log base 2 of b.

因为这就是最基本的情况了，因此当b/2的k次方等于1的时候就停止了1,你说的太对了，就是k等于b的以2为底的对数的时候,你们都坐的挺靠后的啊，我不知道是不是我讲的不太明白？

麻省理工公开课 - 计算机科学及编程导论课程节选