• And what we end up with for the energy then is 2.84 times 10 to the -19 joules.

    我们算出的能量是,2,84乘以10的-19次方焦耳。

    麻省理工公开课 - 化学原理课程节选

  • It is joules per atom. Or, if you multiply by Avogadro's number then you will get joules per mole.

    焦耳每个原子,或者,如果乘以,阿伏伽德罗常数你会得到焦耳数每摩尔。

    麻省理工公开课 - 固态化学导论课程节选

  • That means our energy is equal to 6.626 times 10 to the -34 joules times seconds.

    这意味着能量等于,6,626乘以10的-34次方焦耳每秒。

    麻省理工公开课 - 化学原理课程节选

  • So if you're not in this 77%, let's quickly go over why, in fact, this is the correct answer, . 9 times 10 to the negative 18 joules.

    如果你们不在这77%中,让我们快速的来看一看为什么,这个是正确答案,0,9乘以10的负18次方焦耳。

    麻省理工公开课 - 化学原理课程节选

  • So now we can just take the negative of that binding energy here, and I've just rounded up here or 1 . 4 times 10 to the negative 19 joules.

    等于4是第三激发态,现在我们可以取它结合能的负值,也就是1。4乘以10的负19次方。

    麻省理工公开课 - 化学原理课程节选

  • Also to point out, a lot of times you'll see electron volts instead of joules, this is the conversion factor here just so you all have it in your notes.

    同样也要指出,很多情况下你会看到,电子伏特而不是焦耳,这里是换算因子,你们在讲义上都能找到。

    麻省理工公开课 - 化学原理课程节选

  • And if you do so, you will end up with 1.312 mega joules per mole for this quantity K.

    这样做之后,对于K常量你就能得到2,1。312百万焦耳每摩尔。

    麻省理工公开课 - 固态化学导论课程节选

  • But in terms of SI units, which become much more useful if you're actually trying to use intensity in a problem and cancel out your units, we're just talking about joules per second is what intensity is.

    但是用国际单位制,这个变得越来越有用了,如果你实际上在使用强度,来解决问题和约化单位,我们仅仅讨论每秒钟的焦耳,这就是强度。

    麻省理工公开课 - 化学原理课程节选

  • So, keep in mind that one milliwatt is just the same as saying 1 times 10 to the -3 joules per second.

    所以,请记住1毫瓦,和1乘以10的-3次方焦耳每秒,的说法是等同的。

    麻省理工公开课 - 化学原理课程节选

  • Now you can see 2.18 times 10 to the minus 18 joules can be 13.6 eV.

    你可以看到,2。18乘10到负18焦耳,得到13。6电子伏特。

    麻省理工公开课 - 固态化学导论课程节选

  • Yup. So it's just that ionization energy 94×10-18J that we have experimentally measured, 3 . 9 4 times 10 to the negative 18 joules.

    它就是我们通过实验测得的,电离能3。,我们用所有的这些。

    麻省理工公开课 - 化学原理课程节选

  • So for every photon we have 2.84 times 10 to the -19 joules.

    每一个光子有,2,84乘以10的-19次方焦耳。

    麻省理工公开课 - 化学原理课程节选

  • Occasionally, you'll find you need to cancel out units, because, of course, you're always doing unit analysis as you solve your problems, and sometimes you'll need to convert joules to kilogram meters square per second squared.

    偶然地,你会发现需要消除单位,因为在解题时,经常要做单位分析,所以有时候需要把,焦耳换做,一千克乘以米的平方除以秒的平方。

    麻省理工公开课 - 化学原理课程节选

  • And then the conversion of joules to electron volts is entry 42. If you multiply those two together you will end up with this quantity.

    然后焦耳和电子伏的转换,是在第42个常量,如果你把这两个放一起,你将得到这个数值。

    麻省理工公开课 - 固态化学导论课程节选

  • So hopefully if some of you have your calculators with you, you can confirm the answer that I got, which is that the energy is 7.82 times 10 to the -19 joules.

    所以如果你们带了计算器,希望你们也能确认一下,我们算出的答案,能量等于,7,82乘以10的-19次方焦耳。

    麻省理工公开课 - 化学原理课程节选

  • And we can go through and calculate the value of this quantity in parenthesis. And, when we do so, we get the value 2.18 times 10 to the minus 18 joules.

    我们能进行计算这些值,如果我们这样做,我们能算出是,2。18,乘以10,的负18焦耳。

    麻省理工公开课 - 固态化学导论课程节选

  • We put all of this over the Rydberg constant, which is 2 . 1 8 times 10 to the negative 18 joules, and we want to raise this all to the 1/2.

    除以里德堡常数,我们想把这些所有的再开方,所以我们最后。

    麻省理工公开课 - 化学原理课程节选

  • *10^-19 That is 1.6 times 10 to the minus 19 and I write joules.

    。,然后我又写了焦耳。

    麻省理工公开课 - 固态化学导论课程节选

  • So if we think about the work function for zinc, and the work function for zinc is 6.9 times 10 to the -19 joules, do we expect that when we shine our UV light on the zinc, we'll be able to eject electrons?

    如果我们考虑锌的功函数,它是6,9乘以10的-19次方焦耳,我们是否可以预测当,用紫外灯照射锌时,我们可以射出电子呢?

    麻省理工公开课 - 化学原理课程节选

  • This is 10 to the minus 18 joules for this one atom.

    对单个原子,就是10的负18次方焦耳。

    麻省理工公开课 - 固态化学导论课程节选

  • it's an easy calculation -- we're just taking the negative of the binding energy, again that makes sense, because it's this difference in energy here. So what we get is that the binding energy, when it's negative, the ionization energy is 5 . 4 5 times 10 to the negative 19 joules.

    这个计算很简单-我们,只需要取结合能的负值,同样这很容易理解,因为这就是这的能量差,所以我们得到的就是结合能,当它取负值,电离能就是5。45乘以。

    麻省理工公开课 - 化学原理课程节选

  • So, sometimes you'll find the Rydberg constant in different forms, but just make sure you pay attention to units because then you won't mess them up, because this is in inverse seconds here, the other Rydberg constant is in joules, so you'll be able to use what you need depending on how you're using that constant.

    有时候你们会发现Rydberg常数,会写成不同的形式,但你们要注意,它的单位就不会弄错了,因为这里是秒的倒数,而另一个Rydberg常数是焦耳,所有你可以根据你要怎么使用,这个常数来选择你需要的常数。

    麻省理工公开课 - 化学原理课程节选

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