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OK, so I don't have to, it's a great question, I don't have to create a second one for cmp.
但是参数的顺序是相反的，好，那么我就不必，这是个很不错的问题,我就不必再创建。
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So, it's a trivial matter, by looking at what is the weight and how far does it drop, to say OK, how much work is done by the paddle wheel.
好，让我们看看重物的质量,以及它下落的距离，就知道桨轮做了多少功。
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OK, and you can see that this thing ought to unwrap, it's going to keep extending out those multiplications until gets down to the base case, going to collapse them all together.
好，你可以看到这种方法,是怎么解决的,他一层层的将乘法展开一直到最底层,然后将他们一起乘起来。
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There's a much bigger thing that I'm a part of and if I don't accomplish everything I want to in this life, it's ok.
我属于更大的一个世界,如果我没能在今世完成一切目标,没有关系。
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It's OK to use certain fundamental constants that come in a lot of calculators, so there's nothing we can do about that. That's OK.
当然允许使用,一些普通计算器里都有的基本常数，我们不会连这些都不让用，这是没问题的。
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cause we only have couple of minutes, Ok, it's alright So, for next time, you are going to read about Death in Venice...the introduction that's the movie we're going to watch next week ? But, what do you read for next time?
因为我们只剩几分钟了，可以，没问题,那么，下一次,你们要读《魂断威尼斯》，的介绍,这是我们下周要看的电影,那你们下一次上课之前读什么呢？
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OK. I know. It looks boring. But it's a structure of the things I want to think about when I go through trying to take a problem and mapping it into a iterative program.
好，我知道这看起来有点无聊,但是这是我要去以迭代的方式,去解决一个问题采取的,措施的大致结构。
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It's constant pressure. OK, so now, last time you looked at the Joule expansion to teach you how to relate derivatives like du/dV.
这是恒压的，好，上节课你们,学习了焦耳定律,以及怎样进行导数间的变换。
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Let's check it out. I've written a little bit of a test script here, so if we test cell sort, and I've written this so that it's going to print out what the list is at the end of each round, OK.
我们来检查检查，我写了一个小测试脚本,我写这个脚本来测试单元排序，它能够打印出每一轮结束后,链表的是什么样子的。
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And yeah, I know it comes built in, that's OK, what we want to do is use it as an example to look at it.
对，我知道这个方法可以通过内置的算法，来实现，这没关系，我们只是,把它当做一个例子来讲解。
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OK, so it's time to stop, I did, in fact, get caught up.
好，时间要到了，我最终还是讲完了。
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It's not complete and it's not accurate, but it's OK to kind of think of it in terms of how far we're getting away from the nucleus.
这并不完整，也不精确，但是假如只是想想,我们在离原子核越来越远的话，还是没问题的。
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OK, once it gets to the end of that, what's it going to do? It's going to come down here and, oh. What's that doing? Well I cheated when I started. I said, somebody's giving me a perfect square, I'm looking for the square root of it. But suppose 15 I gave this thing 15, and asked it to run.
好，一旦到了循环的最后，程序会去做什么？程序会跳到这里来,噢，这是干什么的？好吧,当我开始的时候我有点小作弊的意思,我说过，我得到了一个完美的平方数,我要求这个数的平方根,但是假设下我得到的数是。
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It's a sigma bond, - and it's going to be -- N2sp3 no. OK, it's going to be nitrogen 2 s p 3, because it's a nitrogen atom, 1s and then hydrogen 1 s.
它是sigma键，它是-,不，OK，它是，因为这是个氮原子，然后是氢。
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So this isn't-- OK. And you're also close. It's going to be linear but how many times do I go through this?
每次能丢掉一半，所以这里不是-,好的，但你也很接近了,他可能是线性的，但我得遍历多少次呢？
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And what does that say? It says, let's assume I want to do k searches of a list. OK.
如果我们假定要在列表中做k次搜索,在线性的情况下，假定是一个未排序的情况。
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So I'm going to go over here, and I'm going to type test search-- I can type and if you look at your handout, it's just a sequence of tests that I'm going to do OK. So initially, I'm going to set up the list to be the first million integers.
大家可以看看你们的课堂材料，那儿有一些我要做的实验,好，一开始我先去建立个，含有一百万个integer的数组,对，这有点儿简单,但是这给我提供了这样一个有序的数组。
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So it's OK to not specify. I want to point out, pz whether you're in the p x, the p y, or the p z, unless a question specifically m asks you to specify the m sub l, which occasionally will happen, but if it doesn't happen you just write it like this.
我想指出的是，无论你在px，py或，除非一个问题特别地,让你指出l下面的，这种情况有时会发生，这样就可以了,但是如果它不做要求你们写成。
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OK. So it's just adding 1 to x.
好了这就是给x加1。
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On the other hand, if I want to sort it first, OK, if I want to do sort and search, I want to sort it, it's going to take n log n time to sort it, and having done that, then I can search it in log n time.
我先排序，好的，如果我想排序再搜索，我要排序，这需要花n，log，n时间排序，然后做完了，我们能花log，n时间搜索,啊，哪一种更好呢？恩，呵呵。
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First of all, two parameters. It's OK. All it says is, when I call this, I need to pass in two parameters for this to work. All right? Now, if I want to use that, I'm going to use a second piece of code here, called Barnyard. I'm going Barnyard to read in a couple of values, convert them into integers, and then I'm going to use solve to get a solution out.
注意我得到了什么,第一，两个参数,它的意思就是我调用这个函数，我得给它输入两个参数，明白了吗？,现在如果我要使用它我得用,这里的第二段代码，也叫,我将读入一组值，将它们转化为整型,然后我会用solve得到一个解决方案。
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