Now, to get to the number of neutrons, what we do is go up here to the upper left.

现在，看看中子数，我们要做的，是看到这左上方。

麻省理工公开课 - 固态化学导论课程节选

And step seven is how many electrons do we have left over that are going to go into lone pairs? How many?

而第七步是我们剩下,多少电子成为孤对电子？多少？

麻省理工公开课 - 化学原理课程节选

So let's start somewhere; what we're going to do is we'll refer back to this other picture, which is why I left it here.

就从这里开始着手吧,我们先来参考一下之前的图像,所以我之前没有擦掉它

耶鲁公开课 - 博弈论课程节选

The next thing that we want to do is figure out do we have any bonding electrons left.

下一步要做的是看看我们,还有没有剩下的成键电子。

麻省理工公开课 - 化学原理课程节选

And, of course, all that's left is this positive pudding. So that's not going to do anything either. And what he found when he did this experiment, was that the count rate with still 132 000 counts per minute.

剩下的是带正电的布丁,也不会产生什么影响,结果他实验上观测到,计数器测得每分钟132000下,所以到目前为止,他可以说实验。

麻省理工公开课 - 化学原理课程节选

Conversely, if you think the goalie's going to shoot to the right with probability more than a ?, then the best you can do is represented by the pink line, and that's shooting to the left, or if you think the goalie's going to dive to the right with the probability more than a ?, the best you can do, your best response is to shoot to the left.

相反如果你认为门将扑向右侧的概率,大于?的情况下,此时你最佳策略用粉线表示,即从左路射门,也就是说如果你觉得门将扑向右路的,概率大于?的话,你最好选择从左路射门

耶鲁公开课 - 博弈论课程节选