First of all, it's clear from the Pythagoras' theorem that a is the square root of ^2 + ^2.
首先,根据毕达哥拉斯定理,勾股定理在西方被称为"毕达哥拉斯定理"
All right, this is actually a very old piece of imperative knowledge for computing square roots, it's attributed to Heron of Alexandria, although I believe that the Babylonians are suspected of knowing it beforehand.
好,这是一个很古老的,关于计算平方根的程序性知识,是亚历山大的海伦提出的,不过我怀疑在那之前,巴比伦人就已经猜想过了。
And if we go ahead and square that, then what we get is a probability density, and specifically it's the probability of finding an electron in a certain small defined volume away from the nucleus.
我们得到的是,一个概率密度,它是,在核子周围,某个很小的,特定区域,找到电子的概率,所以它是概率密度。
It weights big deviations a lot because the square of a big number is really big.
使偏离的权重更大,一个数的平方是一个更大的数
It seems like it's not a news flash that religion is playing an extremely important part in our public square conversations, in our political life, in how we are making decisions on questions of poverty.
这似乎并非一条简讯,宗教发挥着极其重要的作用,在我们在公共场所的谈话中,在我们的政治生活中,在我们如何针对贫困问题做出决策。
take the derivative of this, get the velocity vector and you notice his magnitude is a constant Whichever way you do it, you can then rewrite this as v square over r.
对这个式子求一次导,就能得到速度矢量,你会发现其模长是常数,不管用什么方法,加速度也可以写成 v^2 / r
It was over here. Because the square root of a quarter is not smaller than a quarter it's bigger than a quarter. Right?
答案超出了这个区间,因为0。25的平方根会比0。25大,是应该比0。25大对不对?
Remember, I said when we do a bisection method, we're assuming the answer lies somewhere between Well, what is the square root of a quarter? It is a half.
记住,我提过当我们用二分法的时候,我们假设答案处于,上边界和下边界之间,0。25的平方根是多少?,是0。5。
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