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It's very simple. It's this: if I know what I'm doing, it is almost inevitably the case that you would know also.
实际上十分简单：,如果我知道我创作的是什么，那么你很可能也知道我创作的内涵。
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And so it's usually the case that you can get a higher return if you're willing to take more risk.
同样很常见的例子是,所以如果你愿意冒高风险,你可能就会有高回报。
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If you could introduce that gene you'd make the chemical, in this case it's a protein called vascular endothelial growth factor.
通过导入一种生成特殊化学物质的基因,这种疗法中指的是一种蛋白,叫做血管内皮生长因子
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In the opposite case, if you have a compression, then it's the opposite of expansion.
绝热压缩，的情况，与此相反。
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So that means it's not possible, if we've made these stipulations in the first place, to have a case where l equals 1.
这说明我们之前的假设,ｌ等于１不可能的。
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Now if this is the case, it seems to me that one has found a loophole in Gadamer's conservatism about what the reader can do.
如果是这样的话，我认为大家在葛达玛对,读者理解能力的保守主义论中,能找到一个漏洞。
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And that is not likely to be the case if it's the person who is nearby. Right?
这和我们说的,近距离产生爱情不是一回事儿？
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But if you throw off the environment, in this case, the animal's biology, it's drive for certain nutrients is in concert with the food it has access to.
如果让它们换个环境,这种情况下,这些动物的生理特性,即它们有多少动力去获取某些营养元素,是与其食物源状态有关的
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.. What I'm going to do now-- let's start out with the case where-- now it's going to get a little bit more complicated if we drop the independence assumption.
我现在要做的是-,让我们从案例开始-,接下来的情况会比刚才的复杂一点,因为我们去掉了“相互独立“这一前提假设。
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So what Christine is arguing is, even though it's the case that 2 is not a dominated strategy, if we do the process of iterative deletion of dominated strategies and we delete the dominated strategies, then maybe we should look again and see if it's dominated now.
克里斯汀说的是,即使选择立场2不是劣势策略,如果我们迭代剔除劣势策略,然后我们剔除掉了劣势策略,然后再来回头看看还有没有劣势策略了
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I was just finding very tunnel vision-like, the smallest elements at that moment in time which means I don't know anything about the other elements other than they are not the smallest and so no matter what with Selection Sort I had to repeat this again and again and again and if you do out the math it's roughly N squared steps in the worst case as well.
我只有一个狭窄的视野，只知道某时刻的最小元素,就意味着我并不知道其他元素的任何情况,只知道它们不是最小的,所以不管怎样，在选择排序中,我就得一遍一遍地重复选择过程,在最坏情况下,大概需要N的平方次比较。
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So I'm first going to look for something that's not in the list, I'm going to see, is minus 1 in this list, so it's going to be at the far end, and if I do that in the basic case, bam.
如果我试试第一种最基本的方法,噢，一下就完成了对不对？,因为这种方法查了下第一个元素，然后发现目标数比较下，因为目标数小于第一个元素。
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So in fact, it is the case, if you look at data, and by the way, that's the way I ended up setting a lot of these parameters and playing with it, was comparing what my simulation said to historical stock data.
所以实际上，在这个例子中，如果你看到数据，顺便说一下，这就是我设置很多变量,然后编程的方式，也就是把我的仿真程序得到的结果,和历史股票数据进行比较。
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So it is always the case that I can only know what I know if it's a question of being communicated with, having something rendered intelligible for me, negatively.
所以我们总是这样地认识事物,我们和人交流时，总是被动地认识符号。
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There's the base case. If it's longer than one, what do I want to do? Well I'd like to check the two end points to see are they the same character? And if they are, then oh, I just need to know is everything else in the middle a palindrome?
如果只有一个元素也是回文，这是基本事件,如果比一个长的话那么我应该怎么做？,我将会查看两头是否相同？,如果是的,我只要知道中间剩下的部分是不是回文即可？
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So, what's the idea? If I know what my hash function does, it maps, in this case characters into a range zero to 256, which is zero to 255, I create a list that long, and I simply mark things.
我知道我的哈希函数做什么,在这个例子中，它将字母，映射成0到255的256个数字，我创建了一个这么长的列表，并且我只是简单的标志这些东西。
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So for example, if you look at the 1 s orbital here, you can see that actually it is lower in the case of the multi-electron atom than it is for the hydrogen atom.
所以举例来说，如果你看到这里的1s轨道,你可以看到实际上,多电子原子情况的。
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Okay, so with your little clicker you can press one, two, three, or four depending on which one of these you believe is the case and let's see if the--if it registers.
拿着表决器的人可以,根据你认为的答案 在一到四中任一项,然后看看它是否注册了
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