• Well if I-- you know, with let me say it differently. I don't need to worry about how checking is done, it's handled inside of that function.

    好,如果你们知道,抱歉,让我们换种说法,我不必担心检查工作,是则会么做的,这是在方法体内部进行的。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • If I were you, I would let it go.

    我要是你的话,我就不会追究了。

    If I were 实战 - SpeakingMax英语口语达人

  • Remember that this molecule, let's look at the blue one wouldn't be the same if I turned it upside down.

    让我们记住,如果我把蓝色的,单链倒过来,那么这条链和原来不一样了

    耶鲁公开课 - 生物医学工程探索课程节选

  • Finally, let's do it in green, let's look at the payoffs, the expected payoffs if I shoot to the right.

    最后,用绿线来表示吧,我们来看看我从右路射门的预期收益

    耶鲁公开课 - 博弈论课程节选

  • If I haven't solved the problem, let me solve it, and store the answer away for later reference.

    让我解决它,然后保留答案以备下次调用。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • But if you step back and reflect on it, "Well, let's see, I was eating a sandwich and suddenly the sandwich was the Statue of Liberty, except the Statue of Liberty was my mother.

    但当你退一步,仔细回想,让我想想,我当时在吃三明治,然后突然,三明治变成了自由女神像,不过这个女神是我的母亲

    耶鲁公开课 - 死亡课程节选

  • As I say, the syllabuses should be accessible on the Classsv2 server; however, I've had problems with that in the past and you should please let me know if it's not.

    你们可以在2号课程服务器上下载大纲;,不过我曾经下载不了,如果现在还不能下的话,一定要告诉我。

    耶鲁公开课 - 现代诗歌课程节选

  • If I pull the one kilogram mass and I let it go, it does something, some acceleration.

    如果我拉 1 千克重的物体并松手,就会获得一个加速度

    耶鲁公开课 - 基础物理课程节选

  • This is--let's see if I have it.

    这一个,我们来看看。

    耶鲁公开课 - 金融市场课程节选

  • Perhaps you ought to reexamine your religious values to see if they meet your needs in life. A religious experience can be a beautiful addition to living, if you put it in the proper perspective and do not let it-- I think it's "warp," "warp you."] Read some books on ethical culture."

    你或许该重新审视自己的宗教价值观来判断,他们是否符合你生活中的需要,宗教经历可以成为,生活中美好的额外事物,如果你从一种适当的角度,不让它,我认为此处是印刷错误,你们看到一个warf的词了吗?,我认为是歪曲,歪曲你的想法,多读一些民族文化的书籍“

    耶鲁公开课 - 1945年后的美国小说课程节选

  • And yeah, I know you know how to do it, but let's think about what might happen if I wanted to do that.

    对,我知道你们知道该怎么做,那么让我们看看如果我,想要完成的话会发生什么。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • We're checking the end test and incrementing, actually I was going to, I commented that out for a reason you'll see in a second, but I, normally I would keep this on, which would let me, at each step, see what it's doing. If I ran this, it would print out each step. Which is helping me make sure that it's incrementing the right way.

    对不对?进行终结测试然后递增,实际上我要,因为某些你们,马上要明白的原因我把这里注释了,但是我通常会一直这么做,这样能让我看到每一步都做了什么,如果我运行这个程序,它会在每一步都,进行显示,这能帮助我让我确信程序是,在以正确的方式递增。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • there that we want to highlight. In particular, -- notice-- let me highlight it for you, if I can find it with the wrong glasses on-- we've got these return commands.

    这里还有一些我们要引起注意的变化,特别是注意这个,让我给你们强调一下-,看看我能不能戴着这副度数不对的眼镜。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So I'm going to check to see if- really can't read that thing, let me do it this way-- right, I'm going to increase the number of compares, and I'm going to check to say, is the thing I'm looking for at the i'th spot in the list?

    让我们这样做吧-好-,我会去增加比较次数的计数器,然后去看看在第i处的元素,是不是我要找的呢?,这里s的意思就是,给定数组的?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Actually for that, I can just use, if I'm lucky, function F5, which didn't work, so let me try it again,here we go.

    实际上这一次,我是想用用,如果我够幸运的话,用下F5,噢,怎么不灵,让我再试试,好了。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Let's bind z eh let's bind z to the-- f if I could type it would help-- say, f of 3. OK?

    让我们给z赋值--如果我能打字就好了-,比方说?

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • Basic idea, before I even look at the code, is pretty simple. If I've got a list that is sorted, in let's call it, just in increasing order, and I haven't said what's in the list, could be numbers, could be other things, for now, we're going to just assume they're integers.

    我们可以说基本的思想是很简单的,如果我有一个排好序的数组,让我们认为这个数组是递增的吧,我并没说数组里元素是什么,可能是数字,也可能是其他的东西,现在我们假设是integer类型的数字吧,最简单的方式就是这么做了:

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • - These ones should curl, see if I can - oh, not bad. Let's run it.

    这些东西可以卷上去,让我们看看,结果不错,让我们来运行一下程序。

    麻省理工公开课 - 计算机科学及编程导论课程节选

  • So the best response for Player 1, as a function of what Player 2 chooses, q2, is just equal to the q1 hat in this expression and if I solve that out carefully, I will no doubt make a mistake, but let's try it.

    这个就是参与人1的最佳对策,它是参与人2策略q2的一个函数,它和之前的q1帽那个表达式是相等的,虽然我是很仔细地计算的,还是有可能算错的,我来验证一下

    耶鲁公开课 - 博弈论课程节选

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