How many people vote for that this is a reversible process? I've got one vote back there two votes, three votes, four votes. Anybody else?
有多少人认为,这是一个可逆过程?有一个,两个,三个,四个,还有别的人吗?
Seventeen against thirty, twenty-four against thirty And by this stage I've got nothing the rest of that list in.
这个列表中已没有任何元素了,那么我可以将那个列表里剩下的元素,添加进去。
I've got two states here, three states here, two here, I need four, and if I can come up with these bonds, four, by the Hund rule I'd fill them like this.
我们已经有2个状态在这里,3个在这里,2个在这里,我需要4个,如果我能想到这些键,四个,通过洪特规则,我们就能像这样排布。
If I want a copy of the string, I've got to whip out my week 1 skills of just iterating with a four loop from left to right and make copies of those characters.
我需要那个字符串的一个拷贝,我使用,第一周的技巧,从左到右做四次迭代,然后复制这4个字符。
As we come back in to this, I think we've got a situation where the piano keeps playing the four-note motive, the part like he was building it up for tension.
回到这里,我想情况是这样的,钢琴一直弹奏着四音节的动机,这个部分像是钢琴在制造紧张气氛
The next time down I've got four versions.
八次,实际上。
Down here, I've just got two things to merge, and then I've got things of size two to merge and then things of size four to merge. But notice a trade off. I have n operations if you like down there of size one.
但是n的大小是不同的,是吗?在这里我们只要合并两个元素,然后是合并长度为2的列表,接下来是合并长度为4的列表,但是观察一下之间的权衡关系。
Up here I have n over two operations of size two. Up here I've got n over four operations of size four.
最下面有n个规模为1的操作,接着上面有n/2个规模为2的操作,再上面有n/4个规模为4的操作。
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