-
So, what we're saying is that we have n equals to 4, and m sub I being equal to negative 2.
我们说的是ｎ等于４,ｍｌ等于－２
-
F Then I'm going to print a capital F just % 1f C to be aesthetically interesting equals another %.1fc.
然后我将打印大写字母,使其比较美观的，等于另一个。
-
And what I want to point out here is this angular dependence for the p orbitals for the l equals 1 orbital.
这里我要指出的是,ｌ等于１的ｐ轨道随角度的变化。
-
So I could have written right here immediately CvdT equals Cv dT, and that was the end of my derivation.
于是我在这里就可以直接写,来它等于，完成了整个推导。
-
The power of linearity is F=k1+k2 if I come across f of x, y, z equals k1 plus k2, if it is a linear equation, I don't have to go and solve it all over again.
线性的威力是,一个方程，如果它是个线性方程，那么我就不用再去解他了。
-
So the version I'd like you to have uses, that, greater than rather than equals that I had in my handout.
因此我希望大家用我说的这个，把课堂手册中的等于换成大于,这里cmp方法。
-
Well, I'm going to write on the board, "shield equals moon," and you can schematize it with, let's say, "A equals A'." A'?
我会在黑板上写下“屏障和月亮一般大“,你们可以在脑海里概括一下，“两者相等“？
-
The formula is-- I could write it this way: price equals one hundred minus this.
公式是,可以这样写,价格等于100减去这些
-
So similarly, I would find that ?2 2 equals 1 plus B S1 and this is the best response of Player II, as it depends on Player I's choice of effort S1.
同理可得?2等于1+B*S1,?2是参与人II的最佳对策,因为它与参与人I的策略S1有关
-
So, first, if I point out when l equals 0, when we have an s orbital, what you see is that angular part of the wave function is equal to a constant.
首先，如果ｌ等于０,那就是ｓ轨道，你们可以看到,它波函数的角度部分是一个常数。
-
All the energies are negative because it is a bound system. I start up here with n equals one.
所有能量级都是负数，因为它是一个束缚系统,在这里我从n等于1讲起。
-
It's reversible, that means that p external, equals p. I'm doing it very slowly so that I'm always in equilibrium between the external pressure and the internal pressure so I can go back and forth.
我都可以不损失能量，而把过程逆向进行,整个过程中的,每一步都保持平衡,现在我们来分别。
-
Let's do another one that I know, 32, and that equals zero.
让我们试一下另一个我们知道的，32，那是等于。
-
System of linear equations. What are the equations here? Well, I could say, you know, the number of pigs plus the number of 20 chickens equals 20, right? Because we've got 20 heads. And then what else do I have?
如何解决这个问题呢？,用线性方程式的办法来解决，等式是什么呢？你应该知道,猪的数量加鸡的数量等于,对吧？因为我们有20个头？
-
If I do x equals 42, I'm not going to put the 42 here, where am I going to put it?
如果，x，=，42，我不会把42放在这里，我把它放在哪里？
-
And that's why I use double equals.
这就是我用双等号的原因。
-
I bought a number of two-period bonds such that the value of my purchase exactly equals the proceeds that I get from shorting the one period bond, so I've made a zero wealth transaction.
我买入了一定数量的两年期债券,其成本刚好等于我卖空,一单位一年期债券获得的资金,我做的是零成本交易
-
I could do this. I could call this n equals one, the fundamental frequency.
我可以这样做，我将n等于，基频。
-
And I'm using the so-called "assignment operator," a single equals sign to store in n what?
我用了一个复制操作符“,一个等号向n中存储了什么？
-
So I'm done when b minus k equals 1, or k equals b minus 1.
因此b-k=1或k-b=1的时候，我就可以停下来了。
-
I just go through these equations, 3 but be careful to Z equals three.
我只检查这些方程式，但是注意了，Z等于。
-
And I could call these others n equals two, n These are harmonics.
我将其他的n等于，等于3，n，equals，three。,这些是和声。
-
In which I said c p 1 dot x equals 1.0.
请注意我上面是怎么做的,创建了cp1和cp2后。
-
If you look at the ground state in two different systems -If you look at the ground state which is n equals one, think about this, if I increase the proton charge, the Coulombic force of attraction is greater.
如果你观察两个不同系统的基态,当你观察n，等于1的基态时，试想一下，如果我增加质子电荷，相互吸引的库仑力就会更大。
-
Why did I say if self dot price equals return?
为什么我会说如果self。price等于0就返回呢？
-
So this code is identical functionally nonswitch c to the last implementation we saw, nonswitch.c, but I'm just ever-more emphatically saying, "In case 1," that is when n equals 1 -- or when case 2 applies -- when n equals 2 or when n equals 3 do what?
所以这些代码到最后的实现上，功能是,完全相同的，但是我想要再次强调一下，“在case，1“，那是当n等于1时1,或者当case，2适用-,当n等于2或者当n等于3，它将做什么？
-
And this is now consistent with my claim that I have sorted a list of size N equals 1.
这与我之前所说的是一致的,我已经将N为1的一个序列排好了序。
-
Let me go ahead and call print F. I'm going to say A equals A and then I need a percent D, backslash, comma A; so this is a little bit of -- more syntax than would be nice, %d but I'm just saying, literally, A equals percent D, and I'm plugging in the value of A for percent D.
我们继续调用printf，我说明A等于,然后我需要%d，反斜杠n，逗号;,所以这个有点--偏向逻辑的，而不偏向美观的，但是我刚说了，字面上，A等于，我用%d插入了A的值。
-
Okay, so I'm going to draw for the case, I'm going to draw the best response of Player I and I'm going to draw the best response for Player II in a minute, for the case B equals 1/4.
好的,我们要画这个案例的图像,我要在图中画出参与人I的最佳对策,一会还要画出参与人II的最佳对策,在这里B等于1/4
-
So now, instead of having p external p2 equals to p2 here, I put p1 and I let this whole thing go reversibly.
也就是说,现在开始的外界压强不是，而是p1，整个过程都是可逆的。
应用推荐