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I declare a variable called n. I'm not giving it a value yet, so I had better be careful.
我申明一个变量n，我先不给它赋值，所以我最好小心点。
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What's going on underneath the hood is we'll see pictorially X today is that when I declare this X, this variable X here.
底下所做的，我们将看到,当我声明这个X，这个变量。
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So A gets 1, B gets 2, now the swap function itself starts executing line by line; so I declare a chunk of memory called temp.
所以A等于1，B等于2，现在swap函数自己开始,一行一行地执行，所以我声明了,叫做temp的一块内存。
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This is copy2.c. At the very beginning I, again, demand say something and then I declare s1 to be a string, aka char *, and I store in s1 the string the user types in.
这是copy2。c，在开头打印一句话，然后声明s1是一个字符串，也叫做char，*，然后把用户输入的字符串存储在s1中。
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Then I do the same thing on line two and I declare something called "y."
然后我在第二行做了同样的事情,我声明了“y“
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So now, henceforth, when you say, to declare a function, I am declaring a function here but down here am I quote unquote defining it or implementing it.
从此以后，当你说，声明一个函数，我在这里声明了一个函数,但是到这里我定义它或执行它。
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It's a common mistake to make if you forget that I've actually declared that variable up top, but wait a minute, I know any time that I use a variable, I have to declare it.
这是一个通常犯的错误，如果你忘了,之前在前面已经声明了这个变量，等等，我知道在任何时候,我使用一个变量，我必须声明它。
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char * s1 Then I go ahead and declare a char * called s1.
然后我声明。
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increment I then declare increment early on.
在之前我声明了。
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Now because among its contents is the prototype for print F, that is why, very simply, I can call print F without having to declare its prototype myself.
现在因为在它的内容中是printf的原型，这就是为什么我可以不声明printf函数的原型,而可以调用它。
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And actually, if I don't want to clobber, as we say, overwrite the value of my variable, ; I could declare another one and store the return value in Y; Y so now I have two ints in memory; X and Y, 3 one with two, one with three.
实际上，如果你不想彻底清除，像我们说的，覆盖那个变量的值，我可以申明另一个变量Y，并在Y中保存那个返回值;,现在内存中有两个int数，X和，一个的值为2，一个为。
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> Initially, how come I don't have declare temp as what?
>，最初，为什么我不声明temp成什么？
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