so I'm heating up the system in this path here, and then to connect the 2 endpoints here, a constant temperature path.
需要再用,一个等温过程,这两个状态。
Now to make that happen, it's not adiabatic, right. If I wanted to do that, I'd need a heating element or something to cool, so I could make that temperature change happen, right.
要实现这点,它就不会是绝热的,对吧,如果我想做到这点,我需要一个加热元件或什么制冷的东西,这样我才能让温度变化。
And on the other side of that temperature you end up heating if you compress.
而在另一边的温度上,压缩气体将导致升温。
Or I could have a non-adiabatic, I could take the same temperature change, by taking a flame, or a heat source and heating up my substance. So, clearly q is going to depend on the path.
也能改变温度,绝热指的是没有热传递,在非绝热条件下,也同样可以升温,比如用火或者热源加热,这样,q也应当与路径有关。
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