The experts at N.I.H.say you may have to repeat this process a few times.

VOA: special.2010.03.31

This is equal to zero. So this irreversible process this Joule-Thomson process, is a constant enthalpy process. Delta h for this process is equal to zero.

等于0。所以这个不可逆过程,也就是焦耳-汤姆逊过程,是一个等焓过程。

麻省理工公开课 - 热力学与动力学课程节选

Adiabatic q equal to zero. It's also delta H 0 which is zero. The two didn't necessarily follow because remember, delta H is dq so p is only true for a reversible constant pressure process.

在这个过程中ΔH等于,绝热的所以q等于0，而ΔH也等于,这两个也不一定有因果关系,因为，记住，ΔH等于dq只有在恒压。

麻省理工公开课 - 热力学与动力学课程节选