Adiabatic q equal to zero. It's also delta H 0 which is zero. The two didn't necessarily follow because remember, delta H is dq so p is only true for a reversible constant pressure process.

在这个过程中ΔH等于,绝热的所以q等于0，而ΔH也等于,这两个也不一定有因果关系,因为，记住，ΔH等于dq只有在恒压。

麻省理工公开课 - 热力学与动力学课程节选

This is equal to zero. So this irreversible process this Joule-Thomson process, is a constant enthalpy process. Delta h for this process is equal to zero.

等于0。所以这个不可逆过程,也就是焦耳-汤姆逊过程,是一个等焓过程。

麻省理工公开课 - 热力学与动力学课程节选

For example, if t* is the time you hit the ground, then t* satisfies the equation h - 1/2 g ^2 = 0.

例如,如果在 t* 时刻落地,那 t* 就满足等式 h - 1/2 g ? ^2 = 0

耶鲁公开课 - 基础物理课程节选

So our bond order for h e 2 is going to be equal to 0.

所以He2的键序等于0。

麻省理工公开课 - 化学原理课程节选

And, that gives you a number for the fluorine, minus 0.29. Now, if you do the same for the hydrogen, you'll come up with the same number.

然后给出F的数字，负的0。29，如果同样的用H来计算，你会得到一样的答案。

麻省理工公开课 - 固态化学导论课程节选

Therefore, from experiments, u is only a function of temperature for an ideal gas, H and therefore from these experiments, 0 we come out with delta H dH/dp is equal to zero.

因此，从实验可以得出,对于理想气体u只是温度的态函数，因此从这些实验中我们得到Δ,偏H偏p等于。

麻省理工公开课 - 热力学与动力学课程节选

Because temperature is constant H only 0 cares about temperature. and that's equal to zero.

因为温度是常数，而H只和温度有关,所以这等于0，如果这等于。

麻省理工公开课 - 热力学与动力学课程节选