So we want to have constructive interference to form a bond, where as if we had destructive interference, we would not be forming a bond.

我们需要,相干相长来成键，如果，相干相消了，就不能成键，所以这时候。

麻省理工公开课 - 化学原理课程节选

And ultimately we are going to get to this state where we are going to form a bond.

最终我们将得到这个状态,即形成一根键。

麻省理工公开课 - 固态化学导论课程节选

Because if we think about wave behavior of electrons and we're forming bonds, then what we have to do is have constructive interference of 2 different electrons, right, to form a bond, we want to and together those probabilities.

如果我们考虑,电子的波动行为,并且，我们要成键的话,我们要,把，这些概率，加在一起,如果。

麻省理工公开课 - 化学原理课程节选

So, that's his gift to us: the Lewis structure, and the idea that you could share electrons and form a covalent bond.

这就Lewis给我们的礼物，Lewis结构，你能够通过公用电子,形成共价键。

麻省理工公开课 - 固态化学导论课程节选

These 2 are going to come together like this, and the first bond that we're going to form is going to be a sigma bond, right, so we see that here. If we're looking head on, we see they form a sigma bond.

它们两个会靠近到一起，首先会形成的是,一个sigma键，对吧，我们在这里可以看出来，我们看到它们形成一个sigma键。

麻省理工公开课 - 化学原理课程节选

If we have, coming along this z axis, another carbon atom, we can actually form one bond between the two carbon atoms there.

如果我们在z方向，有另外一个碳原子，我们可以在,两个碳原子之间形成一个键。

麻省理工公开课 - 化学原理课程节选

So it already should make sense why we have that p orbital there, in order to form a pi bond, we're going to need a p orbital.

这里有p轨道是很合理的,为什么我们在这里有P轨道，为了形成一个π键，我们需要一个p轨道。

麻省理工公开课 - 化学原理课程节选

So if we do this and we form the molecule ammonia, let's switch to a clicker question, and have you tell me what the bond angle - is going to be in ammonia -- HNH Actually, let me draw it on the board as you look -- actually, can you put the class notes on, since you don't actually have your notes to refer to.

如果这样做的话，我们就可以形成氨分子，让我们来做一个课堂练习,你们告诉我氨分子中的键角是多少-,键角，the，h，n，h，bond，angle。,实际上让我在黑板上画出它来，这样你们可以看到实际上-,你能把课堂讲义放出来吗，因为你们没有讲义可以参考。

麻省理工公开课 - 化学原理课程节选