In this case, 6 valence electrons for each oxygen, so we have 18 total valence electrons.
在这种情况下,每个氧原子都有六个价电子,因此我们总共有十八个价电子。
Right? If that was the case in that code, then my complexity is no longer log, because I need linear access for each time I've got to go to the list, and it's going to Lisp be much worse than that.
这里的复杂度不再是对数的了,因为每次在列表中,查找需要线性访问,可能还要糟糕,其实,有些编程语言,如。
First one, when I write a piece of code, especially code that has branches in it, when I design test cases for that piece of code, I should try and have a specific test case for each possible path through the code.
第一点,当我们写代码的时候,尤其是一些含有分支语句的代码的时候,当我为这些代码,设计测试用例的时候,我应该为每一个可能的程序路径,都设计一个特别的用例。
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