The guest list for the dinner provided a sample. Among those seated in the State Dining Room were the first two Muslims elected to the U.S.Congress Keith Ellison and Andre Carson.

VOA: standard.2009.09.02

We give them a list of areas in the business, and they get to select their first, second, third choice.

在我们给出的公司业务的很多领域中，做出第一，第二，第三选择。

斯坦福公开课 - 戴尔CEO-Michael.Dell谈创业和发展课程节选

So the first thing we'll do is, we'll print the element, in this case it will be a list right? Because it's a list with two lists in it.

因此这儿我们要做的第一件事，就是要显示元素，在这儿元素就是数组了对不对？,因为这个数组包含了两个数组。

麻省理工公开课 - 计算机科学及编程导论课程节选

This is the first time we have in Christianity someone attempting to say,"This is the authoritative list.

这是基督教里面第一次有人说,“这些是权威书目。

耶鲁公开课 - 新约课程节选

If you look at his book, again in the first chapter, he gives a list of countries-- it's based on an analysis that some others--that Professors Dimson, Marsh, and Stanton used in their 2002 book.

如果你再看看他在书中所讲的第一章，他列出了一些发达国家的名单-,这是根据其他一些人分析得出的,如迪姆森，马什及斯坦顿教授，在他们2002年出版的书中都用过。

耶鲁公开课 - 金融市场课程节选

So I'm first going to look for something that's not in the list, I'm going to see, is minus 1 in this list, so it's going to be at the far end, and if I do that in the basic case, bam.

如果我试试第一种最基本的方法,噢，一下就完成了对不对？,因为这种方法查了下第一个元素，然后发现目标数比较下，因为目标数小于第一个元素。

麻省理工公开课 - 计算机科学及编程导论课程节选

And that's like kind of hoping that the element you're searching for is the first in the list and the last in the list. Maybe.

也就是希望要找的元素,在数组的头部或者尾部,情况可能是这样的。

麻省理工公开课 - 计算机科学及编程导论课程节选

If I look for, say, minus 1, you might go, gee, wait a minute, if I was just doing linear search, I would've known right away that minus one wasn't in this list, because it's sorted and it's smaller than the first elements.

如果我要查找-1，你可能要怒了，呵呵，等一等，如果我用的是线性查找，我不会知道-1不在这个列表中,但是列表是排好序的,1又比第一个元素小。

麻省理工公开课 - 计算机科学及编程导论课程节选

Sure. So that says one should be the first element in my merge list.

所以可以确定1应该是合并后的,列表的第一个元素。

麻省理工公开课 - 计算机科学及编程导论课程节选

It says, well I'm going to print out first and last just so you can see it, and then I say, gee 2 if last minus first is less than 2, that is, if there's no more than two elements left in the list, then I can just check those two elements and return the answer.

然后它计算了尾点和开始点的差,如果小于2的话,也就是说数组中的元素小于等于，我对这两个元素进行比较,然后返回结果就可以了，否则的话，我们就去寻找中值点，注意它是怎么实现的,首先这个指向一个列表的开头。

麻省理工公开课 - 计算机科学及编程导论课程节选

I've added the ability to have more complex data structures here. But I dropped a hint in the first lecture about what you could computer with things. In fact if you think for a second about that list, you could ask what can I compute with just that set of constructs?

我添加了使用更复杂的数据结构的能力,但是我在第一节课给大家了了一个,关于你可以用什么来做计算的暗示,实际上如果你思考,这个列表一会儿的话,你会问我可以用？

麻省理工公开课 - 计算机科学及编程导论课程节选