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You know that if you took a derivative of this, you will find v of t is v0+at.
如果你对这个式子求一次导,你将会得到v=v0+at
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Let me find v.
让我们了来求 v
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And our job is to find out what is the mathematical description of this path, this line in p-V's case that connects these two point.
我们的任务,就是找出，描述这条曲线的方程。
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I don't really care what key he's in 'cause I don't have absolute pitch, but I can find well, maybe it's a I,VI,IV,V,I chord progression or a I, I IV V I V,I progression or I,IV,V,I.
我也不需要知道他所用的调号，因为我不知道确切的音高，但是我能听出其中的和声，可能是一个，I，VI，IV，V，I级的和声进行，或者，是一个I，V，I的进行，或者。
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If you solve for that, you find y-y0=v0^/, and if you put in the v_0 I gave you, which was what, 10?
如果你解这个式子,你会得到y-y0=v0^/,如果再把我给你的v0代入,那个数是多少 10
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What happens is, you will find that v^=v0^+2a times .
结果就是v^=v0^+2a
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v du/dV under constant temperature. du/dT v under constant volume. You use the Joule expansion to find these quantities.
像偏u偏v，恒温下的偏u偏,恒容下的偏u偏,你们知道怎么运用焦耳定律。
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If you want to find the speed there, you put the equation v^=v0^-2g.
如果你想求出那一点的速度,可利用方程v^=v0^-2g
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It just turns out that if you put the v^2 and you put the r, and r is 93 million miles, you will find the acceleration is small enough for us to ignore.
这样的话,如果你把 v^2 和 r 代进去,r 是 9300 万英里,你会发现加速度小得足以被忽略
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