Step three in our Lewis structure rules is to figure out how many electrons we would need in order for every single atom in our molecule to have a full valence shell.

路易斯结构规则的第三步是,找出让分子中每个原子的价壳层,都排满应该需要多少个价电子。

麻省理工公开课 - 化学原理课程节选

And if we go on to step three where we figure out how many we would need for full octets, it's just going to be 2 times 8, so we have 16.

而如果我们继续到第三步,判断一下填满所有“八隅体“需要多少个价电子，结果应该就是二乘以八，也就是十六个。

麻省理工公开课 - 化学原理课程节选

If you can figure out why fails on three letters instead of 12, you'll be more than half way to solving the problem.

如果你能明白为什么程序,在输入三个字母的单词的时候没法运行,你就已经解决了问题的一半了。

麻省理工公开课 - 计算机科学及编程导论课程节选

We've played it three times, Let's try and figure out what the equilibria looked like in this game.

我们做了三次,我们试着解决,此博弈中的均衡是什么样子

耶鲁公开课 - 博弈论课程节选

Our step three is to figure out how many bonding electrons that we need, or excuse me, how many total electrons that we need to fill up our octets, so that's just going to be 4 times 8, which is 32.

我们的第三步是判断,我们需要多少个成键电子，不好意思，是我们总共需要多少个电子,才能填满所有“八隅体“,那么这就应该是四乘上八，也就是三十二。

麻省理工公开课 - 化学原理课程节选

So let's look at another example, Li2 let's take lithium 2 and see what we can figure out here. In lithium 2, we have two atoms of lithium, each have three electrons in them.

让我们看另外一个例子，我们看一看,看我们能得到什么，在Li2中，我们有两个Li原子，每个带有3个电子。

麻省理工公开课 - 化学原理课程节选