The $2.4 billion figure approved by the Global Fund to Fight AIDS, Malaria and Tuberculosis is $350 million less than last year's amount, which was set before the full effects of the world economic slump were known.

VOA: standard.2009.11.15

So, once we figure out what our probability of backscattering is, we'll just raise that to the 1/2, and we'll multiply that by 12 . 20 centimeters.

所以一旦我们,知道了散射概率，我们开根号。

麻省理工公开课 - 化学原理课程节选

And the figure was that some 2,000 people die as a result of accidents each year using cell phones.

数据显示每年有2000人左右,因开车时使用手机，而死于车祸。

耶鲁公开课 - 公正课程节选

And if we go on to step three where we figure out how many we would need for full octets, it's just going to be 2 times 8, so we have 16.

而如果我们继续到第三步,判断一下填满所有“八隅体“需要多少个价电子，结果应该就是二乘以八，也就是十六个。

麻省理工公开课 - 化学原理课程节选

So I want to figure out the best response of Firm 1 as a function of the price chosen by Firm 2.

我想找出公司1的最佳对策,并用公司2价格的函数表示

耶鲁公开课 - 博弈论课程节选

The way that we can figure this out is using something called bond order, and bond order is equal to 1/2 times the number of bonding electrons, minus the number of anti-bonding electrons.

我们可以用叫做,键序的概念来弄明白它，键序等于1/2乘以成键电子,数目减去反键电子数目。

麻省理工公开课 - 化学原理课程节选

So this is going to be the choice of Player 1, and this is going to be the choice of Player 2, and what I want to do is I want to figure out what this looks like.

这个表示参与人1的策略,这个表示参与人2的策略,接下来我想要知道,这个函数究竟是什么样子的

耶鲁公开课 - 博弈论课程节选

It's always a good first approximation, because you need to start somewhere in terms of drawing Lewis structures, but then if you go and figure out the formal charge and you just have lots of charge separation or very high charges, like a plus 2 and a minus 2 and a minus 1 all different places in the atom, what it should tell you is maybe there's a better structure.

它总是一个好的第一近似，因为在画路易斯结构的时候,你总需要一个起点，但是如果你在算出形式电荷之后,发现有很多电荷分开了,或者说有很高的电荷，比如有一个正二，一个负二，还有一个负一1,在原子的各个地方，这应该就是在告诉你,或许还有一个更好的路易斯结构。

麻省理工公开课 - 化学原理课程节选

So what we're going to do is we're going to figure out Player 1's best response quantity to each possible choice of Player 2, and then we're going to flip it around and figure out Player 2's best response quantity to each possible choice of Player 1, and then we're going to see where those coincide, where they cross.

下面我们就需要表示出,参与人1对于2不同产量下的最佳产量,然后反过来写出,在参与人1的不同产量下,参与人2的最佳产量,然后再来看看这两者在哪里相交

耶鲁公开课 - 博弈论课程节选

So let's look at another example, Li2 let's take lithium 2 and see what we can figure out here. In lithium 2, we have two atoms of lithium, each have three electrons in them.

让我们看另外一个例子，我们看一看,看我们能得到什么，在Li2中，我们有两个Li原子，每个带有3个电子。

麻省理工公开课 - 化学原理课程节选

So, for example, if we needed to figure out the electron configuration for titanium, 4s2 it would just be argon then 4 s 2, 3d2 and then we would fill in the 3 d 2.

所以举个例子,如果我们需要解出钛的电子构型，它会是Ar然后，然后我们填充。

麻省理工公开课 - 化学原理课程节选

So instead you'd have to maybe if you start with wavelength, go over there, and then figure out velocity and do something more like kinetic energy equals 1/2 n b squared to get there.

这时你要先从波长开始，到这，然后算出速度,然后像动能等于1/2nb平方得到这。

麻省理工公开课 - 化学原理课程节选

So what I need to do then is I need to figure out what is Player 1's best response for each possible choice q2 of Player 2.

所以我们要先找出,在参与人2的每个可选策略q2下,参与人1的最佳产量

耶鲁公开课 - 博弈论课程节选

And if we talk about electrons or photoelectrons, again we can describe it in terms of energy, we can talk about velocity, and from there, of course, you can figure out the energy from 1/2 m v squared, and actually we can also describe the electron in terms of wavelength.

如果我们谈论电子或者光电子，我们又可以从能量的角度来描述它，我们可讨论速率，从那里，当然，你可以计算1/2，m，v2得出能量值，而且事实上我们也可以,从波长的角度来描述电子。

麻省理工公开课 - 化学原理课程节选

Now, with this in hand, what I want to do is, and in Firm 2 I have a similar expression, what I want to do is, I want to figure out the Nash Equilibrium of this game.

知道它了以后,因为公司2的表达式也是相似的,接下来我们就可以尝试找出纳什均衡了

耶鲁公开课 - 博弈论课程节选