So, in other words, if we apply some of the storyline 4 5 6 from the previous tale, if s1 happens to be 4, 5, s2 4 5 6 you're just asking the question is 4, 5, 6 equals equals to 1, 2, 3?

换句话说，如果我们运用之前的一些情节,如果s1正好为，正好为1，2，3，6，and，s2，happens，to，be，1，，2，，3，你就会问：,等于1，2，3吗？

哈佛公开课 - 计算机科学课程节选

And what I want to point out here is this angular dependence for the p orbitals for the l equals 1 orbital.

这里我要指出的是,ｌ等于１的ｐ轨道随角度的变化。

麻省理工公开课 - 化学原理课程节选

That energy will be absorbed by the hydrogen atom, n=1 the electron will rise from n equals one n=2 to n equals two.

这能量将会被氢原子吸收，这个电子会从,上升到。

麻省理工公开课 - 固态化学导论课程节选

Okay, so I'm going to draw for the case, I'm going to draw the best response of Player I and I'm going to draw the best response for Player II in a minute, for the case B equals 1/4.

好的,我们要画这个案例的图像,我要在图中画出参与人I的最佳对策,一会还要画出参与人II的最佳对策,在这里B等于1/4

耶鲁公开课 - 博弈论课程节选

So that means it's not possible, if we've made these stipulations in the first place, to have a case where l equals 1.

这说明我们之前的假设,ｌ等于１不可能的。

麻省理工公开课 - 化学原理课程节选

So we are going to put atomic hydrogen Z equals one, 1 ground state n equals one.

氢原子Z等于，基态n也等于。

麻省理工公开课 - 固态化学导论课程节选

We can think about the Lyman series, which is 1 where n equals 1. We know that that's going to be a higher energy difference, so that means that we're going to be in the UV range.

我们可以来看看Lyman系,也就是n等于,我们知道它的能量差更大,所以它在紫外光区内。

麻省理工公开课 - 化学原理课程节选

And if that is the energy to go from n equals one n=2 this is the amount of energy that has to be left as kinetic energy of the electron.

如果这个能量是从n=1到,然后，to，n，equals，two，then,这些能量,会作为电子的动能,被消耗掉。

麻省理工公开课 - 固态化学导论课程节选

So instead you'd have to maybe if you start with wavelength, go over there, and then figure out velocity and do something more like kinetic energy equals 1/2 n b squared to get there.

这时你要先从波长开始，到这，然后算出速度,然后像动能等于1/2nb平方得到这。

麻省理工公开课 - 化学原理课程节选

And I can solve them, and if I solve them out, I'm going to get something like, let me just be careful, I'm going to get something like: 1 minus B S1* is equal to 1, or S1* equals S2* is equal to 1 over .

我们都会解这个方程,如果解完方程,我们会得到,我得仔细点别算错,我们会得到,1-BS1*=1,或S1*=S2*=1/

耶鲁公开课 - 博弈论课程节选

So as I tried to say on the board, we can have n equals 1, 1/2 but since we can't have n equals 1/2, we actually can't have a binding energy that's anywhere in between these levels that are indicated here. And that's a really important point for something that comes out of solving the Schrodinger equation is this quantization of energy levels.

我在这要说的是，我们可以让n等于，但不能让n等于,我们不能得到在这些标出来的,能级之间的结合能，能级的量子化,是从解薛定谔方程中,得到的很重要的一点。

麻省理工公开课 - 化学原理课程节选