So the first thing we'll do is, we'll print the element, in this case it will be a list right? Because it's a list with two lists in it.

因此这儿我们要做的第一件事，就是要显示元素，在这儿元素就是数组了对不对？,因为这个数组包含了两个数组。

麻省理工公开课 - 计算机科学及编程导论课程节选

In the second case, I found in the next smallest element and moved here, taking what was there and moving it on, in this case I would swap the 4 and the 8, and in next case I wouldn't have to do anything.

在第二次遍历中，我找到了,第二小的元素，把它移到这里,把这里原来的元素移到哪里,在这一次遍历中，我会把8和4交换,然后一次遍历，不会做任何事情。

麻省理工公开课 - 计算机科学及编程导论课程节选

He feels that the plot hinges on mysticism or religious mystification. In any case, he makes it very clear, a too vividly apparent transcendent element of sorts, which he says he's worried can only expedite, move up, the day and hour of my professional undoing.

他感觉到了情节是靠神秘或宗教的神秘推动的,无论如何，他的感受非常清晰，一个他担心过于生动的明显的非凡的因素，只能加速，上升，我职业毁灭的时刻。

耶鲁公开课 - 1945年后的美国小说课程节选

If it's there, I'm done, if not, I keep walking down, and I only stop when I get to a place where the element I'm looking for is smaller than the value in the list., in which case I know the rest of this is too big and I can stop.

并且保持遍历,我只在当当前位置的数组元素,大于目标数时停止,这意味着剩下的元素都比目标元素大，但是其他的情况,我还是要遍历完整个数组。

麻省理工公开课 - 计算机科学及编程导论课程节选

How long does it take me to find the k'th element? Linear. Because I've got to walk my way down it. OK? So in this case, you have linear access. Oh fudge knuckle.

线性的！因为我得从头,向下走一步步走,所以这里是线性访问，哦，有问题了吧。

麻省理工公开课 - 计算机科学及编程导论课程节选

Here's the problem. How do I get to the nth- er, the k'th element in the list, in this case?

如何找到第n个元素呢-,在这里，如何找到第k个元素呢？

麻省理工公开课 - 计算机科学及编程导论课程节选